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adamaero
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Homework Statement
The separation between energies of an oxygen molecule is 2061 cm-1 (wavenumber). Treating the molecule as a simple harmonic oscillator whose fundamental frequency is related to its spring constant and reduced mass, calculate the spring constant for an O2 molecule.
meff = 1.33e-26 kg
h = 4.136e-15 eV-s
1 eV = 8065.45 cm-1
Homework Equations
ω = √(k/meff)
k = ω2eff
ω = 2π(v) = 2π(c/λ)
λ = hc/ΔE
∴ k = 2πc/(hc/ΔE)
= 2πΔE/h
The Attempt at a Solution
ΔE = 2061 cm-1 ⇒ 0.2555 eV
k = 3.88*1014 (which just seems way too big)
unit check: eV/(eV-s) so the above value should be even bigger?? (times the speed of light)
k = 1.1644*1023
Actually, I wrongly assumed that the spring constant is unitless.
N/m (force per unit length) or N-m-1
So instead I found this equation, but I don't know how it was derived:
E0 = (h/2)√(k/meff)
k = meff(2E0/h)
k = 1.33e-26(2*0.2555/4.136e-15)^2
k = 203 (which seems reasonable--but I don't get how the equation comes about even knowing .5mv2 = k)
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