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sureman
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goldstone theorem help!
Using goldstone theorem how can I calculate number of massless gauge bosons and massless scalars?
where G1 = SO(2) ∼ U(1) is the global symemtry, and G2 = SU (4) ∼ SO(6) is the gauge symmetry, and G1 ×G2 is completely broken.
dimensions of SU(n)= n^2-1
dimensions of SO(n)=(n(n-1))/2
dimensions of G1 and G2
G1= 1
G2=15
so I know we have n-m massless scalars and I think G2=m and G1xG2=n
so m=15 n=16
therefore
I think we have 1 gauge boson from n-m
and 15 massless scalars from n?
is this close to being right?
Homework Statement
Using goldstone theorem how can I calculate number of massless gauge bosons and massless scalars?
where G1 = SO(2) ∼ U(1) is the global symemtry, and G2 = SU (4) ∼ SO(6) is the gauge symmetry, and G1 ×G2 is completely broken.
Homework Equations
dimensions of SU(n)= n^2-1
dimensions of SO(n)=(n(n-1))/2
The Attempt at a Solution
dimensions of G1 and G2
G1= 1
G2=15
so I know we have n-m massless scalars and I think G2=m and G1xG2=n
so m=15 n=16
therefore
I think we have 1 gauge boson from n-m
and 15 massless scalars from n?
is this close to being right?