Grade 12 Physics: Charge -4.00x10-6C in Electric Field 70N/C

In summary, a particle with a charge of -4.00 × 10-6 C, moving through a uniform electric field of 70.0 N/C directed downwards while moving horizontally at 12.0 cm/s between two plates 10.0 cm apart, has a net force of -2.80 × 10-4 N, an acceleration of -7.00 × 103 cm/s2, and will take 0.0571 seconds to strike one of the plates. The formula connecting the Coulomb force and the electric field is F = qE, the connection between force and acceleration is F = ma, and the dynamics of the charge in a constant electric field is uniform motion. The forces acting on the
  • #1
Grundy
3
0
5. A particle with a charge of -4.00 × 10-6 C moves through a uniform electric field of 70.0 N/C directed downwards. It is moving horizontally at 12.0 cm/s exactly between two plates that are 10.0 cm apart. The particle has a mass of 0.0400 g.
a. What is the net force on the particle?
b. What is the acceleration of the particle?
c. How long will it take to strike one of the plates?
 
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  • #3
so far i have drwn a diagram to what i am dealing with...i am stuck after that
 
  • #4
a)What is the formula connecting the Coulomb force & the electric (electrostatic) field E...?

b)What is the connection between force & acceleration...?

c)What kind of dynamics does the charge have in a constant electric field...?

Daniel.
 
  • #5
What are the forces acting on it? There is a uniform electric field and a charge traveling through.
 
  • #6
dexter posted those three EXTREMELY helpful hints for you. Each of those statements consists of a formula within your textbook/notes. Look for them.
 
  • #7
thanks for the help.. i got it right on the work sheet..thanks a lot
 

FAQ: Grade 12 Physics: Charge -4.00x10-6C in Electric Field 70N/C

What is the magnitude and direction of the electric force on a charge of -4.00x10-6C in an electric field of 70N/C?

The magnitude of the electric force can be found using the formula F = qE, where q is the charge and E is the electric field strength. In this case, the magnitude of the electric force is 2.80x10-4N. The direction of the force is in the same direction as the electric field, which is indicated by the positive sign in the formula.

How does the electric force on a charge of -4.00x10-6C change if the electric field strength is doubled?

The electric force is directly proportional to the electric field strength, according to the formula F = qE. This means that if the electric field strength is doubled, the electric force will also double. In this case, the electric force would become 5.60x10-4N.

What is the direction of the electric field if a charge of -4.00x10-6C experiences an electric force of 0N?

If the electric force on a charge is 0N, it means that the charge is at equilibrium and the forces acting on it are balanced. This can only happen if the direction of the electric field is opposite to the direction of the electric force. In this case, the electric field would be -70N/C.

How does the electric force on a charge of -4.00x10-6C change if the charge is tripled?

The electric force is directly proportional to the charge, according to the formula F = qE. This means that if the charge is tripled, the electric force will also triple. In this case, the electric force would become 8.40x10-4N.

What is the relationship between electric force, charge, and electric field strength?

The relationship between electric force, charge, and electric field strength is given by the formula F = qE. This means that the electric force is directly proportional to both the charge and the electric field strength. If either the charge or the electric field strength is increased, the electric force will also increase. If either of them is decreased, the electric force will also decrease.

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