- #1
Saptarshi Sarkar
- 99
- 13
I was reading a pdf on acoustic grating for my practicals when I saw that the grating element of an acoustic grating is equal to the wavelength of the sound wave. I also checked a few other sources and got the same.
I do not understand why. I know that for an acoustic wave, the standing wave causes the density to change at different locations, making it lower at the antinodes and higher at the nodes. So, the antinodes act as slits.
But, from what I know, the distance between two antinodes is half the wavelength of the wave, so the grating element should also be half the wavelength. Can someone please help me understand this.
I do not understand why. I know that for an acoustic wave, the standing wave causes the density to change at different locations, making it lower at the antinodes and higher at the nodes. So, the antinodes act as slits.
But, from what I know, the distance between two antinodes is half the wavelength of the wave, so the grating element should also be half the wavelength. Can someone please help me understand this.