Gravitation law equation as R approaches zero

In summary, the distance at which the force becomes undefined is based on the mass of the objects. If the objects have a negligible mass, then the force becomes undefined as the separation approaches zero. However, if the objects have a greater mass, the force still exists but becomes larger as the distance approaches zero.
  • #1
pconstantino
40
0
Hello,

in the equation which describes the force as a function of the radius:

F = GMm/R^2


What happens as R approaches zero? or even when R is less than the radius of the planet.

mass m will be inside the planet so this formula seems to break down because m will be pulled from both sides.

how can this be handled?

thank you !
 
Physics news on Phys.org
  • #2
That's an excellent question. For a detailed answer, try looking at http://en.wikipedia.org/wiki/Gauss's_law_for_gravity and the references it cites.

If you have two massive point particles (infinitesimally small) which are gravitationally interacting with each-other, the force becomes undefined as the separation approaches zero. This is a non-physical scenario however, as two particles can never perfectly overlap.

If you're talking about a planet (or other large body) you're exactly right---the equation has to be modified. What "Gauss' law" (the link I posted) states, is that only the mass within the radius you're interested in, matters. (This is an oversimplification, but its the basic idea). If you are half way to the center of the earth, you'll only need to consider the mass within a sphere of radius = half the Earth's radius (approximately 1/8 the mass of the earth). Thus, as your distance from the center approaches zero, the mass enclosed approaches zero, and the force goes to zero.

Does this make sense?
We can go into more math/details if you're interested.
 
  • #3
Two objects cannot match exactly. The distance is calculated between point of gravity of both objects. So in 3d 2 objects cannot overlap exactly on their point of gravity. Then why thinking about it?
 
  • #4
pconstantino said:
Hello,

in the equation which describes the force as a function of the radius:

F = GMm/R^2


What happens as R approaches zero? or even when R is less than the radius of the planet.

Of course there at objects which are VERY massive and their radius is in fact considered to be 0. What happens then is that gravity gets larger and larger as you approach them, until it goes to infinity.
 
  • #5
Raama said:
Two objects cannot match exactly. The distance is calculated between point of gravity of both objects. So in 3d 2 objects cannot overlap exactly on their point of gravity. Then why thinking about it?
Because non-physical questions are still often good ones both per se and for elucidating physical ones. Additionally, as 'objects' are actually waves, they can overlap largely.


Lsos said:
Of course there at objects which are VERY massive and their radius is in fact considered to be 0. What happens then is that gravity gets larger and larger as you approach them, until it goes to infinity.
That's not accurate. In pure gravity theories one would simply say the gravitational force becomes undefined. Otherwise, most unifying theories always preserve a finite radius (e.g. string theory).
 

FAQ: Gravitation law equation as R approaches zero

What is the Gravitation Law Equation as R approaches zero?

The Gravitation Law Equation as R approaches zero is the formula that describes the force of gravity between two objects when their distance (R) is very small, approaching zero. It is written as F = G (m1m2)/R², where G is the gravitational constant, m1 and m2 are the masses of the two objects, and R is the distance between them.

Why is the Gravitation Law Equation important as R approaches zero?

The Gravitation Law Equation as R approaches zero is important because it helps us understand the behavior of gravity in extreme conditions, such as the center of a black hole or the initial stages of the Big Bang. It also allows us to make accurate predictions about the motion of objects in these extreme scenarios.

How does the Gravitation Law Equation change as R approaches zero?

As R approaches zero, the Gravitation Law Equation becomes increasingly stronger, meaning that the force of gravity between two objects becomes greater as their distance decreases. This is because the distance term in the equation, R², is in the denominator, so as R gets smaller, the entire fraction becomes larger.

What is the significance of the gravitational constant in the Gravitation Law Equation as R approaches zero?

The gravitational constant (G) is a fundamental constant in the Gravitation Law Equation as R approaches zero. Its value determines the strength of the gravitational force between two objects, and it is the same for all objects in the universe. Its inclusion in the equation allows us to compare the gravitational force between objects of different masses and distances.

Can the Gravitation Law Equation as R approaches zero be applied to all objects?

The Gravitation Law Equation as R approaches zero can be applied to all objects, as long as their masses and distances are known. However, the equation is most accurate for point masses (objects with negligible size) and becomes less accurate as the size of the objects increases. In these cases, other factors, such as the shape and density of the objects, must also be taken into account.

Back
Top