Gravitational Force as a vector

In summary: I think it will make sense. I hope this is enough information. Good luck!In summary, for the given problem, the gravitational force on the object (m1) as a vector can be calculated using the approximation F = mg in vector notation, taking into account the position vector notation given in the problem statement.
  • #1
karadda
10
0

Homework Statement



r = <0,16,0> m
m1 = 69kg
m2 = 6e24kg (earth)

I need to compute the gravitational force on the object (m1) as a vector

Homework Equations



F = GMm/r^2

The Attempt at a Solution



I get 1.08e14, which is incorrect. I have a feeling I am calculating a magnitude instead of a vector, I'm just not sure what I need to do differently.
 
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  • #2
A vector is a magnitude with a direction attached; there's no difference in calculation. Maybe you needed to specify the direction of the gravitational force?
 
  • #3
karadda said:

Homework Statement



r = <0,16,0> m
m1 = 69kg
m2 = 6e24kg (earth)

I need to compute the gravitational force on the object (m1) as a vector

Homework Equations



F = GMm/r^2

The Attempt at a Solution



I get 1.08e14, which is incorrect. I have a feeling I am calculating a magnitude instead of a vector, I'm just not sure what I need to do differently.

Whoa, hold on. :eek: Something is not right.

The "F = GMm/r^2" equation you mentioned is only valid if the object is at the surface of the Earth or at a greater distance away from the Earth's center that that, if you wish to use the entire mass "m2 = 6e24kg (earth)."

But the way that you worked the equation, you calculated the force on an object 16 m away from the center of the Earth, and that the entire mass of the Earth is confined within a 16 m (radius) ball or smaller ball.

As a first course of action, I'm guessing that might need to take the Earth's radius into account, if the object is ouside the Earth's surface. Could you be more clear on what coordinate system you are using when you state, "r = <0,16,0> m"? I.e, where in relationship to the center of the Earth is r = <0, 0, 0> m?
 
  • #5
Okay, I saw the diagram. Don't use the "F = GMm/r^2" equation for this problem. Theoretically, you could use it and get the same answer, but it overly complicates things.

I believe the question is simply asking you to put the F = mg in vector notation. (F = mg is an approximation that works very well when things don't deviate too far from the surface of the earth. I'm pretty sure you should use this approximation for this particular problem.)

Using the problem statement's examples/definitions of its position vector notation, take note of which directions relate to which elements within the vector notation. Then put F = mg into this notation using the same conventions.
 

FAQ: Gravitational Force as a vector

What is gravitational force as a vector?

Gravitational force is a type of force that acts between two objects with mass. It is a vector quantity, which means it has both magnitude and direction.

How is gravitational force represented as a vector?

Gravitational force is represented as a vector by using arrow notation. The length of the arrow represents the magnitude of the force, and the direction of the arrow represents the direction of the force.

What is the direction of gravitational force?

The direction of gravitational force is always towards the center of mass of the larger object. For example, the direction of gravitational force between the Earth and an object on its surface is towards the center of the Earth.

How is the magnitude of gravitational force calculated?

The magnitude of gravitational force is calculated using the equation F = G(m1m2)/r^2, where G is the universal gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between their centers of mass.

Can gravitational force be a negative vector?

Yes, gravitational force can be a negative vector if it is acting in the opposite direction of a positive vector. For example, if two objects have opposite charges, the gravitational force between them will be negative.

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