Gravitational Forces on Ship Stranded Near Black Hole

In summary: You'll need to calculate the gravitational field at 10 km and at 10.1 km and then calculate the difference.Note that the gravitational field is often expressed in units of acceleration (m/s^2).In summary, a ship in the shape of a cylinder with a length of 100m and a mass of 1000kg, along with its occupants, has strayed too close to a black hole with a mass 100 times greater than the sun. The nose of the ship is pointed towards the black hole and is 10km from the center. The total force on the ship is 1.3*10^17N. The difference in the gravitational fields acting on the occupants in the front of
  • #1
rpcarroll
7
0

Homework Statement


A ship in the shape of a cylinder has length 100m, and mass 1000kg with occupants. It has strayed too close to a black hole with mass 100 times greater than the sun (100*2.0*10^30). The nose of the ship is pointed towards the black hole and is 10km from the center of the black hole.
(a) What is the total force on the ship?
(b) What is the difference in the gravitational fields acting on the occupants in the front of the ship compared to those in the rear (furthest from the hole)?


Homework Equations


Gravitational Field= (Fg/m)
Fg=G * [(m1*m2)/r2]


The Attempt at a Solution



(a) Fg= [1000kg*(100*2.0*1030]/100002m=1.3*1017N

Not sure about b, do I need to calculate Fg at the two different distances (front and rear of the ship)?
 
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  • #2
rpcarroll said:

Homework Statement


A ship in the shape of a cylinder has length 100m, and mass 1000kg with occupants. It has strayed too close to a black hole with mass 100 times greater than the sun (100*2.0*10^30). The nose of the ship is pointed towards the black hole and is 10km from the center of the black hole.
(a) What is the total force on the ship?
(b) What is the difference in the gravitational fields acting on the occupants in the front of the ship compared to those in the rear (furthest from the hole)?


Homework Equations


Gravitational Field= (Fg/m)
Fg=G * [(m1*m2)/r2]


The Attempt at a Solution



(a) Fg= [1000kg*(100*2.0*1030]/100002m=1.3*1017N

Not sure about b, do I need to calculate Fg at the two different distances (front and rear of the ship)?

I'm assuming that's what they want to know. :)
 
  • #3
Pretty much that's the way to do it looks like to me.

Those in front are at 10 km and those in the back are at 10.1 km.
 
  • #4
The idea of question b is for you to figure out how large the "spaghettification" effect is.
You'll know what it is once you've calculated it :-)
 
  • #5
So when they ask for the 'total force on the ship', is it just measured at 10km and not, say, 10.05 (I think that would be the center of mass of the cylinder shaped ship)?
 
Last edited:
  • #6
rpcarroll said:
So when they ask for the 'total force on the ship', is it just measured at 10km and not, say, 10.05 (I think that would be the center of mass of the cylinder shaped ship)?

With part a) yes I think you can use the center of mass to calculate the total force. (10.05 km would be good, though at these numbers the precision within 1/2 % is not exactly that important.)

For part b) they are looking for the difference in the gravitational field.

That only involves the mass of the black hole, not the whole ship. That's given more simply by GM/r
 

FAQ: Gravitational Forces on Ship Stranded Near Black Hole

What exactly is a black hole and how does it affect a ship stranded near it?

A black hole is a region in space with an incredibly strong gravitational pull that is so powerful that it can trap even light. When a ship gets stranded near a black hole, the intense gravitational forces can cause significant disruptions in its movement and structure.

How close does a ship have to be to a black hole for the gravitational forces to be dangerous?

The distance at which a black hole's gravitational forces become dangerous for a ship depends on the size and mass of the black hole. Generally, the closer a ship is to the event horizon (the point of no return), the stronger the gravitational forces will be. However, even at a safe distance, the ship may still experience significant gravitational effects.

Can gravitational forces from a black hole cause a ship to be pulled into the black hole?

Yes, if a ship gets too close to a black hole, the gravitational forces can become so strong that it will be pulled into the black hole. This is known as the "spaghettification" effect, where the ship will be stretched and torn apart by the immense gravitational pull.

How can a ship stranded near a black hole escape its gravitational forces?

In most cases, it would be nearly impossible for a ship to escape the gravitational forces of a black hole once it gets too close. However, if the ship has powerful enough engines and can generate enough thrust, it may be able to break free from the gravitational pull and escape to a safe distance.

Are there any other dangers for a ship stranded near a black hole besides gravitational forces?

Aside from the intense gravitational forces, a ship stranded near a black hole may also be exposed to high levels of radiation and extreme tidal forces. These can cause damage to the ship's systems and put the crew in danger. Additionally, the extreme gravitational forces can cause time dilation, where time passes differently for the crew on the ship compared to those observing from a safe distance.

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