- #1
lomidrevo
- 433
- 250
Let's assume a binary system with an inclination angle ##i## (angle between the orbital plane and line of sight). Then, according to this source - equations (128) and (129) - for the amplitudes of the tensor polarization modes ("plus": ##+## and "cross": ##\times## polarization) I could write:
$$h_{+} \propto (1 + \cos^2 i) $$
$$h_{\times} \propto (2\cos i) $$
So now, if I would take the extreme cases.. If it happens that we observe merging binaries perpendicular to their orbital plane (##i = 0##), our detector(s) would measure gravitational waves (GWs) with both of the polarization modes, with equal amplitudes. In case we see the orbital plane edge-on (##i = \pi / 2##), then we detect only GWs with "plus" polarization, and the amplitude of the measured distortion is only half when compared to the first case.
Is my understanding correct?
Note: this is not a homework. I've been just curious why most of the visualizations provided on internet shows GWs propagating in the plane of the orbit. The above suggest that radiation emitted perpendicularly to the plane is more intense. But I see, it would be quite difficult to draw these waves
$$h_{+} \propto (1 + \cos^2 i) $$
$$h_{\times} \propto (2\cos i) $$
So now, if I would take the extreme cases.. If it happens that we observe merging binaries perpendicular to their orbital plane (##i = 0##), our detector(s) would measure gravitational waves (GWs) with both of the polarization modes, with equal amplitudes. In case we see the orbital plane edge-on (##i = \pi / 2##), then we detect only GWs with "plus" polarization, and the amplitude of the measured distortion is only half when compared to the first case.
Is my understanding correct?
Note: this is not a homework. I've been just curious why most of the visualizations provided on internet shows GWs propagating in the plane of the orbit. The above suggest that radiation emitted perpendicularly to the plane is more intense. But I see, it would be quite difficult to draw these waves