- #1
SirPencil
- 3
- 0
Homework Statement
What is [H+] and pH for a 100 mM solution of KOH
The Attempt at a Solution
This seems very simple..its only 2 marks but I don't know what I'm doing wrong.
I understand KOH will dissociate into K+ and OH-
pOH=-log(OH) ?
ph + pOH = 14
p[OH]=-log[100x10^-6?]
where and what am i doing wrong?
Thanks for the help!