Solve H= (NI)/ (2(Pi)r): Calculate Current, Voltage

[dietwater]

Homework Statement

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Homework Equations

H= (NI)/ (2(Pi)r)
V=IR

The Attempt at a Solution

a)

total resitance = 100ohms?
from this would the current be 0.12A

over 1ohm resistor: 0.12V

not sure if this is correct even. Any help would be much appreciated.

 

[Defennder]

I think you misread 'H' here. H in the question doesn't refer to the magnetic field strength and the formula you provided here refers to the H-field in a torus.

Also in your answer you disregarded the inductor. Bear in mind that once you open the circuit, you can't treat the inductor as a short-circuited wire. What you should do is to write out the KVL loop equation, bearing in mind the potential drop across the inductor is L(di/dt), where i is the time-varying current through the inductor. Then you'll get a differential equation which you then have to solve for the current. Plugging in a initial value will help you find the unknown constant of integration.

 

[Mene]

The equation H = (NI)/ (2(Pi)r) is known as the magnetic field equation, where H represents the magnetic field strength, N is the number of turns in the coil, I is the current, r is the radius of the coil, and Pi is the mathematical constant 3.14. This equation can be used to calculate the magnetic field strength at a specific point in space, given the values of the other variables.

To calculate the current, we can rearrange the equation V=IR to solve for I. This gives us I=V/R, where I is the current, V is the voltage, and R is the resistance. In this case, we are given a total resistance of 100 ohms, so we can use this to calculate the current. Plugging in the values, we get I= 0.12 A.

To calculate the voltage, we can use the same equation V=IR. In this case, we are given a 1 ohm resistor, so we can use this value for R. Plugging in the values, we get V= 0.12 V. This is the voltage across the 1 ohm resistor.

It is important to note that in this equation, H is the magnetic field strength, not the voltage. So, we cannot directly use this equation to calculate the voltage. We can only use it to calculate the current, and then use the equation V=IR to calculate the voltage.

 

[piercas]

b)

To solve for current, we can use the formula V=IR and rearrange it to solve for I. We know that the voltage (V) is equal to H, and the resistance (R) is equal to 100 ohms. Therefore, we can rewrite the equation as I=H/R. Plugging in the value of H from the given equation, we get I= (NI)/ (2(Pi)r*100). This simplifies to I= (N/200(Pi)r). So, the current is equal to N divided by 200 times Pi times the radius (r).

To solve for voltage, we can use the formula V=IR and plug in the value of current we just calculated. This gives us V= (N/200(Pi)r) * 100. This simplifies to V= (N/2(Pi)r). So, the voltage is equal to N divided by 2 times Pi times the radius (r).

In conclusion, to calculate current and voltage in this equation, we need to know the value of N and the radius (r). Without those values, we cannot accurately determine the current or voltage.