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smahapatra3
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Homework Statement
A slab made of unknown material is connected to a power supply as shown in the figure. There is a uniform magnetic field of 0.5 tesla pointing upward throughout this region (perpendicular to the horizontal slab). Two voltmeters are connected to the slab and read steady voltages as shown. (Remember that a voltmeter reads a positive number if its positive lead is connected to the higher potential location.) The connections across the slab are carefully placed directly across from each other. The distance w = 0.15 m. Assume that there is only one kind of mobile charges in this material, but we don't know whether they are positive or negative.
In the steady state, the current moves straight along the bar, so the net sideways force on a moving charge must be zero. Use this fact to determine the drift speed of the mobile charges
Homework Equations
F=q(E+vXB)
Eperp=uEparallelB
The Attempt at a Solution
It's in steady state so I know the electric and magnetic forces are equal. So I think the equation is Eperp=vB. I tried to find E using volts/length. And then divide by B but that was wrong.