Bob S said:I have had the same problem. The Hall Effect probe is a 4-wire device vaguely similar to a Wheatstone bridge in its hookup. Voltage is applied to the top and bottom of the "diamond" and the signal is the difference of the left and right outputs. You can zero-reference these outputs if you have access to +/- 5 or +/- 15 volts for an opamp Vcc and Vee. You have to get an opamp and set up as a differential amplifier. I guess you will want 10k ohm resistors from the left and right sides of the diamond to the + and - inputs of the opamp, and a 100k ohm from the + input to ground (assuming your opamp is tied to +/- 5 or 15 V), and a 100 k ohm resistor from the - input to the output. This symmetric layout rejects the offset, and the opamp output will be single-ended referenced to ground rather than floating differential. Using 10k and 100k resistors gives you a signal gain of 10. If you want a very high input impedance, you will need to use two more opamps on the inputs as gain-of-one voltage followers.
vk6kro said:try this:
http://en.wikipedia.org/wiki/File:Op-Amp_Non-Inverting_Amplifier.svg
http://en.wikipedia.org/wiki/File:Op-Amp_Inverting_Amplifier.svg
You would connect the output of your hall device directly to the input of one of the above.
The gain is given by the ratio of the two resistors in the second case and almost the same in the first.
If you had a voltage change of 0.2 volts in each direction and wanted 1.5 volts in each direction, you would want a gain of 1.5 / .2 or 7.5.
So, you might choose 10 K for the input resistor (or R1) and two 150 Ks in parallel for the feedback resistor (or R2). You need a plus and minus power supply for this op amp and also for the Hall device. The Hall device would require +/- 2.5 volts. That is 4 power sources.
I'd still use a Picaxe chip. You can have PWM out of the same picaxe to give an analog readout if you wanted.
I'm planning to amplify it with a gaussmeter amplifier basically I will replace the sensor it has which is a coil type with a hall type, which is why the high quiesent was a problem and then I'll take the output from the gaussmeter and send it to a Pic MCU.I saw on NVE site that for very low field detection the noise is the limiting factor in their sensors and that some kind of AC modulation/demodulation should be used. Do you know how to implement something like that?vk6kro said:I hope you don't really need microvolt resolution. If you do, there might be problems with mains voltage hum on the signal.
Anywhere near a city will give you big problems at that resolution.
This is how you flash a LED light once a second with a picaxe:
High 2, pause 500, low 2, pause 500, high 2, pause 500... (500 is in milliseconds)
or even
start:
toggle 2
pause 500
goto start
What would you use as a readout? Would it go to a meter or to a computer?
vk6kro said:No. Not really. I've heard of it but never tried it.
I would think that the Earth's magnetic field and the pickup of mains hum would be more serious problems than the noise of the device itself.
Why not build up a separate unit before you try pulling the Gaussmeter to bits. At least you can then get an idea of how serious the noise problems are likely to be.
A Hall sensor quiescent voltage refers to the voltage output of a Hall sensor when there is no magnetic field present. It is also known as the idle or standby voltage.
The quiescent voltage of a Hall sensor is typically measured by connecting a voltmeter across the output pins of the sensor and ensuring that there is no magnetic field present. The resulting voltage reading is the quiescent voltage.
A zero quiescent voltage ensures that the sensor is not affected by any external magnetic fields and is operating in its idle state. This is important for accurate measurement of magnetic fields and for the stability of the sensor's output.
The quiescent voltage of a Hall sensor can be affected by factors such as temperature, power supply voltage, and sensor placement and orientation. It is important to keep these factors consistent for accurate and consistent measurement.
The quiescent voltage of a Hall sensor can be adjusted by using a potentiometer or by applying a bias voltage to the sensor. This can be useful for calibrating the sensor and ensuring that the output is at zero when no magnetic field is present.