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If f is a smooth function defined on the plane then the integral of its gradient over any closed curve is zero.
What about the integral of the 90 degree rotation of the gradient?
In symbols, if grad f = (df/dx , df/dy) its 90 degree rotation is
(-df/dy , df/dx)
What about the integral of the 90 degree rotation of the gradient?
In symbols, if grad f = (df/dx , df/dy) its 90 degree rotation is
(-df/dy , df/dx)