- #36
Lapin Dormant
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In these forums, this page seems to offer something .. .. .. I'll go post there, perhaps.
The telescope is radiating EM to the night sky and is receiving EM from the night sky. The difference is that the net exchange results in the temperature of the 'scope going down very quickly - radiative cooling. The scope will cool much faster if it is pointed at the night sky than if it is left sitting out in the cold with a dew cap on or without a dew cap, but pointing at a building, a row of trees, etc.I was pointing out that the night sky is a powerful heat sink. Any astonomer can explain this to you. A telescope pointed at the dark sky will cool far more rapidly that you would expect by considering the ambient temperature alone. This is pretty basic.
This is pretty wrong. The "night sky", as you're describing it, does not absorb radiation from the telescope, the telescope just emits the radiation and gets no feedback from its environment. In this sense, the night sky is not a heat sink, but rather the lack of a heat source. Any object left to itself will cool with time because it radiates its energy away. If, at the same time, the environment is giving feedback in the form of radiation, then the cooling process will be slower. That's why your telescope cools more slowly when pointed at a radiating source.
You missed my point entirely. The complexity of the reactions by which a blackbody attains its temperature has no relation to the spectrum of its radiation. If it is a true blackbody, its spectral curve is defined, and that curve will look the same no matter how many interactions and energy transfers caused the blackbody to have its current temperature, and no matter what the wavelength of the EM that heated it to its current state.Not true. The EM need only be absorbed once and emitted once to produce a black-body spectrum based on the temperature of the emitter. An object can exhibit a black-body spectrum at one temperature, and then can exhibit a different (based on its temperature) black-body spectrum after being heated or cooled to a different temperature.
I think you need to pick up a good book on statistical mechanics. Equilibrium is not obtained as a result of one event, but is instead the end result of the many complicated interactions in a body (photon absorptions, collisions, etc.). An electromagnetic wave that is emitted from, say, the sun, will impact on the surface of a body (for example, you) and deliver energy to your surface. The particles on your surface will then have higher energies than the particles in your interior. However, because of collisions, vibrations, photon exchanges, etc., the energy will be redistributed throughout your body. A process like this can take a split second, a year, a millenium, or it might not occur at all. We can, however, calculate the approximate time for this process to occur and determine that the early universe should have had no trouble obtaining thermal equilibrium.
Turbot said:Sorry for the imprecision (I left you a pretty good opening there) - when I said that "empty" space is a pure black body, I pute quotes around empty because as the Hubble deep-field exposure show us, it will be impossible to find any direction in space from which we are not receiving radiation from embedded sources in addition to the background temperature of space itself (no matter how slight).
Well, I do know a "little" math. I also understand that if all the radiation that escaped during recoupling escaped at one time and at one average temperature, the redshifted spectrum of that source would retain its blackbody shape, albeit flattened with its peak shifted redward. The question I have arises from my understanding that in the BB model, recombination happened over a long period of time, with the plasma medium becoming more and more transparent to EM as time went on.
Turbot said:The telescope is radiating EM to the night sky and is receiving EM from the night sky. The difference is that the net exchange results in the temperature of the 'scope going down very quickly - radiative cooling. The scope will cool much faster if it is pointed at the night sky than if it is left sitting out in the cold with a dew cap on or without a dew cap, but pointing at a building, a row of trees, etc.
You missed my point entirely. The complexity of the reactions by which a blackbody attains its temperature has no relation to the spectrum of its radiation.
If it is a true blackbody, its spectral curve is defined, and that curve will look the same no matter how many interactions and energy transfers caused the blackbody to have its current temperature, and no matter what the wavelength of the EM that heated it to its current state.
Lapin Dormant said:Should one really be taking advice from a 25 year old, with 34 years of experiance?
That is advice, so please to help me, and any other reader{s} of this, tell me {us?} where you have previoulsy answered his question?SpaceTiger said:I already answered this concern in another thread, but you ignored it. I've noticed that you do that a lot. If you don't understand my explanation, then ask me to elaborate, don't pretend it didn't happen.
Lapin Dormant said:That is advice, so please to help me, and any other reader{s} of this, tell me {us?} where you have previoulsy answered his question?
Have you ever done any studies of statistical propensities of Falsifications?