Heat Absorbed to Melt Ice & Warm Water to 10°C

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In summary, to warm up a 4.00kg block of ice from -20C to 10.0C, the heat it must absorb is calculated by adding the energies required to heat the ice, melt the ice, and heat the resulting water. The specific heat capacity of ice is 2000J/kg-degrees C, the specific heat of water is 4180 J/kg-degrees C, and the latent heat of fusion for ice is 335000 J/kg.
  • #1
Sabres151
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A 4.00kg block of ice is removed from a freezer where its temperature was maintained at -20C. Find the heat that the ice must absorb in order to warm up to its melting point, melt, and then the water warms up to 10.0 degrees. The specific heat capacity of ice = 2000J/kg-degrees C, the specific heat of water is 4180 J/kg-degrees C and the latent heat of fusion for ice is 335000 J/kg.

I don't even know where to start.
Something with this: Q = Cm(delta T)
DeltaT = 30 degrees C
 
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  • #2
you need a 3 energies -

one to heat the ice
one to melt the ice
one to heat the water

th first and third are calculated the way you state (but with different speicifc heats, since they are different for water and ice)
the second is calculated by mass * specific heat capacity
 
  • #3
stunner5000pt said:
you need a 3 energies -

one to heat the ice
one to melt the ice
one to heat the water

th first and third are calculated the way you state (but with different speicifc heats, since they are different for water and ice)
the second is calculated by mass * specific heat capacity

Ok, that clarifies a few things then. Thanks for the help Stunner. Though I'm not exactly sure what "latent heat of fusion" means, I think it applies to the mass equation..
 
  • #4
stunner5000pt said:
you need a 3 energies -

one to heat the ice
one to melt the ice
one to heat the water

th first and third are calculated the way you state (but with different speicifc heats, since they are different for water and ice)
the second is calculated by mass * specific heat capacity

Ok, that clarifies a few things then. Thanks for the help Stunner. Though I'm not exactly sure what "latent heat of fusion" means, I think it applies to the mass equation..
 
  • #5
stunner5000pt said:
you need a 3 energies -

one to heat the ice
one to melt the ice
one to heat the water

th first and third are calculated the way you state (but with different speicifc heats, since they are different for water and ice)
the second is calculated by mass * specific heat capacity

Ok, that clarifies a few things then. Thanks for the help Stunner. Though I'm not exactly sure what "latent heat of fusion" means, I think it applies to the mass equation..
 
  • #6
Sabres151 said:
Ok, that clarifies a few things then. Thanks for the help Stunner. Though I'm not exactly sure what "latent heat of fusion" means, I think it applies to the mass equation..

latent heat of fusion is the amount of energy required per kilogram to melt the ice
 

FAQ: Heat Absorbed to Melt Ice & Warm Water to 10°C

How does heat absorption affect the melting of ice?

When heat is absorbed by ice, it causes the ice molecules to gain energy and vibrate faster. This increased molecular motion weakens the bonds between the molecules, causing the ice to melt. The rate of melting is directly proportional to the amount of heat absorbed.

How much heat is needed to melt ice?

The amount of heat needed to melt ice varies depending on the initial temperature and quantity of ice. It takes approximately 334 joules of heat to melt 1 gram of ice at 0°C.

Can heat absorption also warm water?

Yes, heat absorption can also warm water. When heat is added to water, the molecules gain energy and move faster, causing the water to warm up. The amount of heat needed to warm water by 1°C is called the specific heat capacity of water and is approximately 4.18 joules per gram per degree Celsius.

How much heat is needed to warm water to 10°C?

The amount of heat needed to warm water to 10°C depends on the initial temperature and quantity of water. For example, it would take approximately 41.8 joules of heat to warm 1 gram of water from 0°C to 10°C.

Why does ice melt at 0°C instead of 32°F?

The freezing and melting points of water were originally defined in the Celsius scale, where 0°C is the freezing point and 100°C is the boiling point of pure water at sea level. However, in the Fahrenheit scale, the freezing point of water is 32°F and the boiling point is 212°F. These scales are related by a linear conversion, which is why 0°C corresponds to 32°F.

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