- #1
Helly123
- 581
- 20
Homework Statement
Kinetic energy per mol is 3/2KT
Homework Equations
Q = nC##\Delta##T
U = Q + W
W = -P##\Delta##V
The Attempt at a Solution
1) internal energy = 3/2NKT
2) heat needed to increase temperature of 1 mol ideal gas by 1 degree at constant volume?
Since constant volume, W = 0
Q = Internal change
Q = 3/2NKT= 3/2nRT
3) work done by one mole ideal gas, when increased by 1 degree temperature, constant pressure?
W done = Q - U
4) when volume doubled, how much increased in kinetic energy?
I thought that more volume means less kinetic energy
5) volume doubled, adiabatic condition, final pressure must 0.3 lower than first pressure.
What i focused is on numbers 2 and 3
Can i get a clue?