- #1
Grand
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Homework Statement
The question asks whether it is always true that
[tex]dU=C_VdT[/tex]
and their answer is no, because from the 1st law of TD we derive that:
[tex]dU=C_VdT+\left(\frac{dU}{dV}\right)_TdV[/tex]
However, if we hold the volume constant, dV=0 and therefore the second term disappears, is this right?