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Homework Statement
Find the temperature distribution in the long thin bar −a ≤ x ≤ a with a
given initial temperature u(x,0) = f(x).
The side walls of the bar are insulated, while heat radiates from the ends into
the surrounding medium whose temperature is u = 0.
The radiation is taken to obey Newton’s Law.
Homework Equations
[tex]u_{t} = \alpha^{2}u_{x}_{x}[/tex]
[tex]u_{x}(-a,t) = (h/k)u(-a,t)[/tex]
[tex]u_{x}(a,t) = -(h/k)u(a,t)[/tex]
[tex]u(x,0) = f(x)[/tex]
h and k are constants.
The Attempt at a Solution
My main concern is: I do not know if according to the problem description, the BCs should be as written above OR
[tex]
u_{x}(-a,t) = -(h/k)u(-a,t)[/tex]
[tex]u_{x}(a,t) = (h/k)u(a,t)[/tex]
I had to construct the BCs myself, they were not given explicitly in equation form.
notice that the only difference is that the negative sign has gone from one equation to the other. I would appreciate it if someone could tell me where the negative sign belongs, and perhaps also explain why, I did not fully grasp the explanation I was given in class. Thank You.