- #1
Amith2006
- 427
- 2
Sir,
A man covers his body with a blanket of thickness 4 mm. His temperature is 37 degree Celsius and that of the atmosphere is 27 degree Celsius. If the coefficient of thermal conductivity of wool is 1.2 x 10^(-5) W/m.K , what is the heat lost per hour per square meter area?
I solved it in the following way:
Heat loss = KA(T1 – T2)t/y
Here K = 1.2 x 10^(-5) W/m.K
T1 – T2 = 10 K
y = 4 x 10^(-3)
Heat lost per unit area per hour = [1.2 x 10^(-5) x 10 x 3600]/(4 x 10^(-3))
= 108 Joule
Is it right?
A man covers his body with a blanket of thickness 4 mm. His temperature is 37 degree Celsius and that of the atmosphere is 27 degree Celsius. If the coefficient of thermal conductivity of wool is 1.2 x 10^(-5) W/m.K , what is the heat lost per hour per square meter area?
I solved it in the following way:
Heat loss = KA(T1 – T2)t/y
Here K = 1.2 x 10^(-5) W/m.K
T1 – T2 = 10 K
y = 4 x 10^(-3)
Heat lost per unit area per hour = [1.2 x 10^(-5) x 10 x 3600]/(4 x 10^(-3))
= 108 Joule
Is it right?