- #1
aznkid310
- 109
- 1
Homework Statement
I have uploaded the problem statement and corresponding programs.
Reader is the problem statement
Reader1 is another file that is suppose to help
Homework Equations
I'm just having trouble getting started. I can do the analytical part on paper, but I don't know how to implement this in MATLAB.
In the program for problem 1:
What is the 'A' and 'C' matrix?
I can get some values on paper, but, for example, what is A(i, i+1)? I realize this this the temperature to the left of the node I am interested in, but do I type in some sort of equation?
Similarly for A(i,i), A(i, i-1), C(n)...
Is C(1) = -200 from my solution?
It seems I have to do what is says in the reader1 file, but I don't know how to use it
The Attempt at a Solution
For #1a:
T(x) = C1x + C2
Boundary Conditions: T(0) = 500
T(L = 1m) = 300
Thus T(x) = 500 - 200x
q = -kA(dT/dx) = 37200 Watts, where k = 186 W/m.k
energy balance for internal nodes: q1 + q2 +qV = 0
q1 = kA[ (T_i-1) - T_i]
q2 = kA[(T_i+1) - T_i]
qV = dx = internal heat generation assuming dy=dz = infinite
Finite Diff. eqn: (T_i-1) - (2T_i) + (T_i+1) = 0
For the left boundary node:
q_left side = 0 b/c T = 500k is constant?
therefore q_right side + qV = 0
q_right side = kA[(T_i+1) - T_i] and qV is the same from before
Right Boundary Node:
q_left side = kA[(T_i-1) - T_i] and qV stays the same
How is this implemented in MATLAB?
For #1b:
Boundary Conditions: T(0) = 500
-kA(dT/dx) @ x=1m = hA(Ts -T_inf) [Convective BC]
Assuming C1 is the same from part a (is this correct?): T_inf = 462.8 K
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