Heat transfer in a double pipe HE

[nod32]

Homework Statement

I performed an experiment using a double pipe heat exchanger. Readings were taken at steady state.

Cold water entered the inner tube at 9°C, and its exit temp was 81°C. (flow rate was measured).

The outer tube contained steam at 133°C and this temperature remained constant. Condensate flow rate was measured.

Homework Equations

i) q=U A ΔT(lmtd)
ii) q=m h$_{fg}$ (where hfg is heat of vaporization)
iii) q=m Cp ΔT(bulk)

The Attempt at a Solution

Since the steam did not change temperature but condensed, there was latent heat transfer. q was calculated using ii). (result q=28kW)

I then calculated q using equation iii) applied to the cold water stream. (result q=59kW)

I don't understand why these two results are so far apart. In a perfect system, wouldn't they be equal?

 

[Chestermiller]

Homework Statement

I performed an experiment using a double pipe heat exchanger. Readings were taken at steady state.

Cold water entered the inner tube at 9°C, and its exit temp was 81°C. (flow rate was measured).

The outer tube contained steam at 133°C and this temperature remained constant. Condensate flow rate was measured.

Homework Equations

i) q=U A ΔT(lmtd)
ii) q=m h$_{fg}$ (where hfg is heat of vaporization)
iii) q=m Cp ΔT(bulk)

The Attempt at a Solution

Since the steam did not change temperature but condensed, there was latent heat transfer. q was calculated using ii). (result q=28kW)

I then calculated q using equation iii) applied to the cold water stream. (result q=59kW)

I don't understand why these two results are so far apart. In a perfect system, wouldn't they be equal?

Yes. And, even if there were heat losses, q ii would be higher than q iii, rather than lower. Show us the data.

 

[nod32]

Yes my mistake, I mixed them up. The higher q came from equation ii). I guess that makes sense since not all the released energy from the condensation ends up warming the cold stream.
So this large difference can be attributed to heat losses?

I'm also asked to do an energy balance to verify the accuracy of the heat transfer rates. Isn't that what I just did when I compared the two q values? How would that verify anything, as they would always be different?

 

[Chestermiller]

Yes my mistake, I mixed them up. The higher q came from equation ii). I guess that makes sense since not all the released energy from the condensation ends up warming the cold stream.
So this large difference can be attributed to heat losses?

I'm also asked to do an energy balance to verify the accuracy of the heat transfer rates. Isn't that what I just did when I compared the two q values? How would that verify anything, as they would always be different?

Let's see the data. Flow rates, heat of vaporization at 133, Cp used?

 

[rezeew]

As a scientist, it is important to remember that real-world experiments may not always produce results that align perfectly with theoretical calculations. In this case, it is possible that there were some external factors that affected the heat transfer in the double pipe heat exchanger, such as heat loss to the surroundings or imperfect insulation. Additionally, the equations used may not take into account all the complexities of the system, leading to discrepancies in the results. It is also important to consider the accuracy of the measurements and any potential errors in the experimental setup. Overall, it is normal to have some variation between theoretical calculations and experimental results, and further analysis and refinement of the experimental setup may be necessary to improve the accuracy of the results.