Heater power keeping a room constantly warm from low temperatures outside

In summary, heater power ensures that a room maintains a consistently warm temperature despite low outdoor temperatures by generating and distributing heat effectively.
  • #1
Karma1412
3
1
Homework Statement
The temperature of a room in winter is kept constant at 24 °C by using a heater. The room is separated from the outside, where the temperature is -5.0 °C, by a wall of area 12 m^2 and thickness 0.20 m. The material of the wall has a thermal conductivity of 0.15 W m1 K-1. Estimate the power of the heater.
Relevant Equations
None given, and I can't find any that work or figure out how to use any
I've been trying for 45 minutes and doing research but I can't even find a start to how to approach this. :(

[Mentor Note: New user reminded to always show their work on schoolwork problems. That work is shown in a subsequent post below]
 
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  • #2
I've tried to do the following:
P = AM
M = eoT^4 (e being the emmisivity, o being the constant i think stefen boltzmann)
M = ((Pm^-1)/(oT^4)) x oT^4 (subbing e because emissivity = (power radiated per unit area)/(σT^4)
oT^4 x M = Pm^-1 x oT^4
M = Pm^-1 (cancelling)
and then I have no clue what to do, or if this even makes any sense or if I am using the right formula.
I have also used
Q= (ΔT⋅A⋅k)/d
to calculate
Q=(29 x 0.15)/0.20m
Q= 52.2 / 0.20
Q=261 W
but again I really dont know if what I did is real, ai generated this formula and when I searched for it online I couldn't find it.
 
  • #3
Karma1412 said:
Homework Statement: The temperature of a room in winter is kept constant at 24 °C by using a heater. The room is separated from the outside, where the temperature is -5.0 °C, by a wall of area 12 m2 and thickness 0.20 m. The material of the wall has a thermal conductivity of 0.15 W m1 K-1. Estimate the power of the heater.
Relevant Equations: I'm not sure, but the one's I've found from the research I did seem to be:
Q= (ΔT⋅A⋅k)/d (Im not sure if this formula is real, it's what ChatGPT gave me when I asked for help)
L = σAT^4 (I don't know if it is relevant)
P = AM

I've tried to do the following:
P = AM
M = eoT^4 (e being the emmisivity, o being the constant i think stefen boltzmann)
M = ((Pm^-1)/(oT^4)) x oT^4 (subbing e because emissivity = (power radiated per unit area)/(σT^4)
oT^4 x M = Pm^-1 x oT^4
M = Pm^-1 (cancelling)
and then I have no clue what to do, or if this even makes any sense or if I am using the right formula.
I have also used
Q= (ΔT⋅A⋅k)/d
to calculate
Q=(29 x 0.15)/0.20m
Q= 52.2 / 0.20
Q=261 W
but again I really dont know if what I did is real, ai generated this formula and when I searched for it online I couldn't find it.
The intention is 1D steady state thermal heat conduction through a plane wall.
 
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  • #4
erobz said:
The intention is 1D steady state thermal heat conduction through a plane wall.
thank you, ill do some research on it :)
 
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  • #6
Karma1412 said:
Q= (ΔT⋅A⋅k)/d

Q=(29 x 0.15)/0.20m
What about A?
 
  • #7
Karma1412 said:
Homework Statement: The temperature of a room in winter is kept constant at 24 °C by using a heater. The room is separated from the outside, where the temperature is -5.0 °C, by a wall of area 12 m^2 and thickness 0.20 m. The material of the wall has a thermal conductivity of 0.15 W m1 K-1. Estimate the power of the heater.
Relevant Equations: None given, and I can't find any that work or figure out how to use any

I've been trying for 45 minutes and doing research but I can't even find a start to how to approach this. :(
The temperature of the room is constant. That tells us something about the relationship between heat leaving the room and heat being added to the room.

How does heat leave the room?

How is heat added to the room?
 
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  • #8
Karma1412 said:
I've tried to do the following:
P = AM
M = eoT^4 (e being the emmisivity, o being the constant i think stefen boltzmann)
M = ((Pm^-1)/(oT^4)) x oT^4 (subbing e because emissivity = (power radiated per unit area)/(σT^4)
oT^4 x M = Pm^-1 x oT^4
M = Pm^-1 (cancelling)
This problem is not related to emissivity or radiation.
It is a thermal conduction one.
Energy in form of heat naturally flows through that wall from the warm to the cold space.

Please, see:
https://en.wikipedia.org/wiki/Thermal_conduction#Fourier's_law

https://en.wikipedia.org/wiki/Rate_of_heat_flow

:cool:
 
  • #9
haruspex said:
What about A?
A is the wall area, given in the problem as 12 m^2.
 
  • #10
phyzguy said:
A is the wall area, given in the problem as 12 m^2.
I was asking why it does not appear in the second of the two equations I quoted.
 

FAQ: Heater power keeping a room constantly warm from low temperatures outside

How do I calculate the required heater power to maintain a constant room temperature?

To calculate the required heater power, you need to determine the heat loss of the room. This can be done using the formula: Q = U * A * ΔT, where Q is the heat loss in watts, U is the overall heat transfer coefficient (W/m²·K), A is the surface area of the walls, windows, and roof (m²), and ΔT is the temperature difference between inside and outside. Once you know the heat loss, you can select a heater with an appropriate power rating to compensate for this loss.

What factors influence the amount of heater power needed?

Several factors influence the amount of heater power needed, including the insulation quality of the room, the surface area of walls, windows, and roof, the difference between indoor and outdoor temperatures, the presence of drafts or air leaks, and the efficiency of the heater. Better insulation and sealing can significantly reduce the required heater power.

How does insulation affect heater power requirements?

Insulation plays a crucial role in reducing heat loss. High-quality insulation materials with low thermal conductivity reduce the amount of heat that escapes through the walls, roof, and floor, thereby lowering the heater power required to maintain a constant room temperature. Upgrading insulation can lead to significant energy savings and improved comfort.

Can using a thermostat help in maintaining a constant room temperature efficiently?

Yes, using a thermostat can help maintain a constant room temperature efficiently. A thermostat regulates the heater by turning it on and off to maintain the desired temperature. This prevents overheating and reduces energy consumption by ensuring the heater operates only when necessary.

Is it more efficient to keep the heater on all the time or to turn it on and off as needed?

It is generally more efficient to use the heater as needed rather than keeping it on all the time. Continuous operation can lead to unnecessary energy consumption, especially if the room is well-insulated and retains heat effectively. Using a programmable thermostat can optimize heater usage by adjusting settings based on occupancy and outdoor temperature changes.

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