- #1
metiscus
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Can someone give me quick refresher on what happens when you multiply the heaviside function with the unit impulse?
Typically, the unit step function multiplied by anything simply delays it by the offset in the unit step function. The unit impulse function makes the value defined at only one point. At least I believe this is so... for example:
(n+1)U(n)*d(n-2) = (n-1)u(n-2) right?
Typically, the unit step function multiplied by anything simply delays it by the offset in the unit step function. The unit impulse function makes the value defined at only one point. At least I believe this is so... for example:
(n+1)U(n)*d(n-2) = (n-1)u(n-2) right?