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negation
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Without a detailed sequential diagram, it can be hard to conceive of a mental modelling. Why is it 4g down? Acceleration is always in the direction towards the center, isn't it? Let's just say that when the pilot is at the point (0,-r), he experiences a 4g acceleration towards the center. At the same time, there is a 1g acceleration in the direction towards the ground. But, why, as you'e put it, would the 4g acceleration be in the direction towards the ground? How did this 4g acceleration, initially towards the center changes vector suddenly. It doesn't make sense.BvU said:In post #26:
I feel misread! Please read it again:
While going straight down at constant speed, the pilot experiences 1g downward. This is a vector.
As soon as he pulls the wheel (or what do they call it -- A stick, I realized since then) towards him, a uniform circular motion sets in that requires 4g of acceleration towards the centre. His seat provides the force required for that acceleration. Also a vector, initially pointing to the right. So initially he feels an acceleration of 1 g down, 4g to the right. √17 magnitude total. Gradually going towards 1 g down and 4 g down as well just before point q. Magnitude now 5 g (same direction). He can stand that as per given in the OP. If he's smart he pulls up a little longer, haha. The moment he is going straight again, he experiences 1 g towards the center of the earth.
In post#29:
The 1 g acceleration down does not lead to a free fall. His seat pushes him up to oppose the gravitational force and it also pushes him up with 4g to keep him in a circular motion. These seat forces are in the same direction, hence the 5g.
I'm glad rcgldr helps too. Lok is amused, which is nice. But I resent him saying you are being ignored. I try to help you patiently as best I can to deal with the exercise. Where a circular motion is not exactly a given, but already complicated enough for us, right?
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