Height/diameter relationship of 19 (H8/D8=19)

[nelg]

Hi and thanks for your help in advance Math Help Board Members,

I have this quote:
"The extractor of the 0.1L unit has a volume of 100mL and an internal height/diameter relationship of 19 (H₈/D₈=19)"

Sorry to sound so silly, but can someone please help me work with this equation?
I would like a cylinder that would hold approximately 5.0L.
What should the Height and Diameter be?

Cheers

Nelg

 

[HallsofIvy]

The area of a circle of radius r is \(\displaystyle \pi r^2\). Since the radius is 1/2 the diameter, r= d/2, \(\displaystyle r^2= d^2/4\) so we can write that as \(\displaystyle \pi d^2/4\). A cylinder or diameter d and height h has volume \(\displaystyle \pi d^2h/4\). So we want \(\displaystyle H_8\) and \(\displaystyle D_8\) that satisfy \(\displaystyle \pi D_8^2H_8/4= 5\).
If we also want "an internal height/diameter relationship of \(\displaystyle 19 (H_8/D_8=19)\)" then $$H_8= 19D_8$$ and \(\displaystyle \pi D_8(19D_8)/4= \frac{19\pi}{4}D_8^2= 5\) so \(\displaystyle D_8^2= \frac{20}{19\pi}\).

 

[nelg]

WOW...thanks HallsofIvy!
I'm going to need some time to digest your work.
I am in complete awe and thanks! :D

I'm currently trying to create an Excel spreadsheet that will 'spit out' the volume of the cylinder based on H/D=19 relationship.

This could take me a while...I'll keep you posted

:DNelg