- #1
phantomcow2
- 52
- 0
We just started vectors today and introduced the I and J axes. He insists we use I and J instead of X and Y, that's okay.
So basically here is the question asked:
A person riding a bike has a velocity v=32m/s I + 12m/s J. Determine the magnitude of hte velocity and hte bikes direction. Determine the total distance traveled by the person on the bike after 120 seconds.
SO my first step I would think is to draw quadrant 1 of an XY plane. Is the direction northeast? I would imagine this is the case because there is no mention of any negative velocities, so quadrant 1 is + in both axes.
TO determine the magnitude of velocities...
Do I simply draw a right triangle, with point (0,0) as the vertex with a 90 degree? Move up 32 in the I, and 12 in hte J?
Then use A^2+B^2=C^2 to find the hypotenuse? The hypotenuse being the magnitude?
I THINK that part I have right. BUt it is the total distance that stumps me, can somebody give some insight?
So basically here is the question asked:
A person riding a bike has a velocity v=32m/s I + 12m/s J. Determine the magnitude of hte velocity and hte bikes direction. Determine the total distance traveled by the person on the bike after 120 seconds.
SO my first step I would think is to draw quadrant 1 of an XY plane. Is the direction northeast? I would imagine this is the case because there is no mention of any negative velocities, so quadrant 1 is + in both axes.
TO determine the magnitude of velocities...
Do I simply draw a right triangle, with point (0,0) as the vertex with a 90 degree? Move up 32 in the I, and 12 in hte J?
Then use A^2+B^2=C^2 to find the hypotenuse? The hypotenuse being the magnitude?
I THINK that part I have right. BUt it is the total distance that stumps me, can somebody give some insight?