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enforcer53
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Homework Statement
Consider a wire loop in a 1.88 T magnetic field (coming out of the board at a 55.0° angle). The loop is 0.300 m tall and 0.400 m wide, carrying a 2.90 A current traveling in a clockwise direction. The loop feels a torque that causes the spring to compress. If the spring is compressed by 4.30 mm, what is the spring constant?
The attempt at a solution
This is what i tried. I don't feel I am getting the right answer.
Torque is T = IABsinθ
(2.90 A)(0.120 m^2)(1.88 T)sin(55.0) =0.536
I know that Torque is also = Frsinθ
I then rearranged the formula to get F = Torque/rsinθ (0.536)/(0.15)(sin55) = 4.36 = F
I plug my Force value into the F=kx formula. In order to find k, I did (4.36)/(0.0043) which gave me k = 1013.9
This does not seem correct to me. Where did I go wrong?