- #1
tribalman100
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Homework Statement
The following amounts of substances are added to a 7.25 L reaction vessel at 773K:
(.103 mol CO) , (.205 mol H2), ( 2.1 mol CH4), ( 3.15 mol H20). In what direction will a net reaction occur to react equilibrium.
CO(g) + 3H2(g) --------> CH4(g) + H20 (g)
<-------
Kp= 102 at 773K
The answer to this problem is a slight net reaction occurs to the right because QP (98.4) is slightly less than Kp (102)
The problem i have is everytime i try to do the work i can't get the Qp to = 98.4
If someone will help me i will be very greatful
Homework Equations
The Attempt at a Solution
here is my attempt sry i forgot to post it
first i put all the moles in molarity and got the folloying
CO--- .42 M
H2--- .28
CH4--- .014
H2) --- 2x10-5 when you cube it cause of the coefficient
Then i put a Qp equation
Qp= ( .42)(.28)
--------------------
------( .014)(2e-5)
Final answer i got was Qp= 420000 way off i can't figure out why
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