Help on this would be amazing; centripetal force & projectile motion

In summary, the problem involves calculating the launch velocity, centripetal force, tension, and distance between David and Goliath. The angular speed can be found by dividing the number of rotations by the time, and this will also be the launch speed. The centripetal force can be calculated using the mass, angular speed, and radius. This force must equal the tension in the sling. To find the distance between David and Goliath, the equations of motion can be used, taking into account the 2 m height above David's head.
  • #1
dominus96
51
0

Homework Statement



David used a sling to kill Goliath. The mass of the rock was 2.5 kg and the sling had a length of 1.2 m. If it spun horizontally 2 m above his head 7 times in 3 seconds:

a. What was the launch velocity?

b. What is the centripetal force and tension?

c. How far is David from Goliath?

Homework Equations



Fc=mv^2/r
F=ma
Fc=m4(pi^2)r/t^2

The Attempt at a Solution



I tried setting ma=mv^2/r, but that would only give me the velocity it spins at, not the velocity at which it was launched. And I'm not sure what to do with the 2 m.

Assistance would be great, I've been trying this for 2 hours and still nothing.
 
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  • #2
7 times in 3 seconds gives you the angular speed, which will also be the launch speed. We assume it was rotating about David's head at a constant rate.

From the angular speed you have calculated, you can get the centripetal force. This must equal the tension

For c. you need to use the equations of motion, which is where the 2m comes in
 
  • #3
Thank you
 
  • #4
dominus96 said:
Thank you

I am a little rusty, but I am quite sure that the launch speed does not equal the angular speed. The rock leaves the sling's cirular path in a direction perpendicular to the string.

Angular speed=[tex]\omega[/tex] launch speed=[tex]v_{tangential}[/tex]

Do you know of a relationship between angular and tangential speed?

Casey
 
  • #5
ah crap, yes, i meant the tangentil speed, lol.
 
  • #6
Yes i figured that out, but thanks for the lead. it helps a lot.
 

FAQ: Help on this would be amazing; centripetal force & projectile motion

What is centripetal force?

Centripetal force is the force that acts on an object moving in a circular path, pulling it towards the center of the circle. It is always directed towards the center of the circle and is necessary to maintain circular motion.

How is centripetal force related to projectile motion?

Centripetal force is not directly related to projectile motion, as projectile motion involves an object moving in a curved path due to the combination of its initial velocity and the force of gravity. However, if an object is moving in a circular path as part of its projectile motion, centripetal force will be acting on it to keep it in that circular path.

What factors affect centripetal force?

The magnitude of centripetal force depends on the mass of the object, its velocity, and the radius of the circular path it is moving in. The force is directly proportional to the mass and velocity, and inversely proportional to the radius.

How can I calculate centripetal force?

The formula for centripetal force is Fc = (mv^2)/r, where Fc is the centripetal force, m is the mass of the object, v is its velocity, and r is the radius of the circular path. This formula can be used to calculate the force needed to keep an object moving in a circular path.

What is the difference between centripetal force and centrifugal force?

Centripetal force is the force that pulls an object towards the center of a circular path, while centrifugal force is the apparent force that pushes an object away from the center of the circle. Centrifugal force is often referred to as a "fictitious" force, as it is not a real force but rather a result of the object's inertia trying to keep it moving in a straight line.

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