Help proving a subset is a subspace

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In summary, to prove that the set of all 3-vectors orthogonal to [1, -1, 4] forms a subspace of R^3, we need to show closure under vector addition and scalar multiplication. This can be done by using the fact that orthogonal vectors have a dot product of 0 and showing that the sum of two orthogonal vectors is also orthogonal to the given vector. The hint suggests using distributivity of the dot product to demonstrate this.
  • #1
paulrb
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Homework Statement



Prove that the set of all 3-vectors orthogonal to [1, -1, 4] forms a subspace of R^3.

Homework Equations



Orthogonal means dot product is 0.

The Attempt at a Solution



I know the vectors in this subspace are of the form
[a,b,c] where a - b + 4c = 0.
However I don't know how to use this to show there is closure under vector addition and scalar multiplication.
 
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  • #2
Let v_1 and v_2 be two vectors orthogonal to the given vector (call it a), i.e.

[tex] v_1 \cdot a = 0 [/tex]
[tex] v_2 \cdot a = 0 [/tex]

Now, using these, all you have to do is show that

[tex] (v_1 + v_2) \cdot a = 0[/tex]

HINT: Use distributivity of the dot product.
 

FAQ: Help proving a subset is a subspace

What is a subset?

A subset is a collection of elements that are contained within a larger set. It can be thought of as a smaller group of objects that are all part of a larger group.

How can I prove that a subset is a subspace?

To prove that a subset is a subspace, you must show that it satisfies three criteria: closure under addition, closure under scalar multiplication, and contains the zero vector. This can be done by using the subset's definition and the properties of vector spaces.

What is closure under addition?

Closure under addition means that when two elements in the subset are added together, the result must also be in the subset. In other words, the subset must be closed under the operation of addition.

What is closure under scalar multiplication?

Closure under scalar multiplication means that when an element in the subset is multiplied by a scalar (a constant), the result must also be in the subset. In other words, the subset must be closed under the operation of scalar multiplication.

Why is it important to prove that a subset is a subspace?

Proving that a subset is a subspace is important because it ensures that the subset follows all the rules and properties of a vector space. This allows for the use of mathematical operations and theorems on the subset, making it easier to study and understand.

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