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hivesaeed4
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f=9-x^2-y^2 and u=i-j
The directional derivative comes out to be Du f(x,y)=-sqrt(2)+sqrt(2)
I'm going to find the directional derivative and could someone kindly point out the mistake because I am getting a different answer and it's important I understand how to do this question:
Du f(x,y) is simply the ∇f.u (note u is a vector)
Now ∇f=-2xi-2yj and ∇f.u=(-2xi-2yj).(i-j) = -2x+2y. Help?
The directional derivative comes out to be Du f(x,y)=-sqrt(2)+sqrt(2)
I'm going to find the directional derivative and could someone kindly point out the mistake because I am getting a different answer and it's important I understand how to do this question:
Du f(x,y) is simply the ∇f.u (note u is a vector)
Now ∇f=-2xi-2yj and ∇f.u=(-2xi-2yj).(i-j) = -2x+2y. Help?