- #1
William12
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Water is being sprayed at a hot flowing material to cool it from 350F to 290F. Let's assume that steam is produced when the water hits the hot material. How would I set up the heat transfer equation to solve for the mass flow rate of water required to cool it from 350 to 290?
Assumptions
Specific Heat of Water = 4.186 KJ/Kg-K
Specific Heat of Hot Material = 2.177 KJ/Kg-k
Mass Flow Rate of Hot Material = 1.512 Kg/s
Latent Heat of Vaporization = 2260 KJ/Kg
Temperature of Water = 75F
Evaporation Temperature of Water = 212FThis is how I set up the equation...
Energy absorbed by Water + Latent Heat of Vaporization - Energy released by Hot Material = 0
MFRwater*Cwater*(TwaterOUT-TwaterIN) + Lwater*MFRwater - MFRmaterial*Cmaterial*(TmaterialOUT-TmaterialIN) = 0
Now, solving for MFRwater ...
MFRwater = [MFRmaterial*Cmaterial*(350-290)] / [Cwater*(212-75) + Lwater]
When I plug in the numbers, I get a REALLY small answer. Am I missing a part of the equation? Is my algebra wrong? Am I using the right value for the specific heat of water, later heat of vaporization, and evaporation temperature of water? Or did I do everything correctly?
Assumptions
Specific Heat of Water = 4.186 KJ/Kg-K
Specific Heat of Hot Material = 2.177 KJ/Kg-k
Mass Flow Rate of Hot Material = 1.512 Kg/s
Latent Heat of Vaporization = 2260 KJ/Kg
Temperature of Water = 75F
Evaporation Temperature of Water = 212FThis is how I set up the equation...
Energy absorbed by Water + Latent Heat of Vaporization - Energy released by Hot Material = 0
MFRwater*Cwater*(TwaterOUT-TwaterIN) + Lwater*MFRwater - MFRmaterial*Cmaterial*(TmaterialOUT-TmaterialIN) = 0
Now, solving for MFRwater ...
MFRwater = [MFRmaterial*Cmaterial*(350-290)] / [Cwater*(212-75) + Lwater]
When I plug in the numbers, I get a REALLY small answer. Am I missing a part of the equation? Is my algebra wrong? Am I using the right value for the specific heat of water, later heat of vaporization, and evaporation temperature of water? Or did I do everything correctly?