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Rha1828
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2) A Uniform Boars has a mass of 1.5kg and length of 100cm, Note the Weight is negligible.
A) Where should it be supported so that it will balance a 10g mass places at an end, a 60kg mass on the other end, and a 40kg mass placed 30 cm to the 10g mass?
The answer should be 0.511m
a. First you need to convert all g to kg and cm to m
Therefore,
(10g)(1X10-3kg1g) = 0,010kg
(40g)(1X10-3kg/1g) = 0.040kg
(60g)(1X10-3kg/1g) = 0.060kg
(30cm)(1X10-2m/1cm) = 0.30m
(100cm)(1x10-2m/1cm) = 1.0m
(0cm)(1x10-2m/1cm)= 0 m
Using the center of mass equation you get
Xcg = W1X1 + W2X2 + W3X3 / W1 + W2 + W3
0A
Therefore,
Xcg = (0.010kg)(0m) + (0.060kg)(1.0m) + (0.040kg)(0.30) / (0.010kg) + (0.060kg) + (0.040kg)
= 0.0720kg.m / 0.110 kg
= 0.645 m
I am not sure where I went wrong and why I have a higher number then the answer. Any help would be great!
thank you!
A) Where should it be supported so that it will balance a 10g mass places at an end, a 60kg mass on the other end, and a 40kg mass placed 30 cm to the 10g mass?
The answer should be 0.511m
a. First you need to convert all g to kg and cm to m
Therefore,
(10g)(1X10-3kg1g) = 0,010kg
(40g)(1X10-3kg/1g) = 0.040kg
(60g)(1X10-3kg/1g) = 0.060kg
(30cm)(1X10-2m/1cm) = 0.30m
(100cm)(1x10-2m/1cm) = 1.0m
(0cm)(1x10-2m/1cm)= 0 m
Using the center of mass equation you get
Xcg = W1X1 + W2X2 + W3X3 / W1 + W2 + W3
0A
Therefore,
Xcg = (0.010kg)(0m) + (0.060kg)(1.0m) + (0.040kg)(0.30) / (0.010kg) + (0.060kg) + (0.040kg)
= 0.0720kg.m / 0.110 kg
= 0.645 m
I am not sure where I went wrong and why I have a higher number then the answer. Any help would be great!
thank you!