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depeche
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I have to prepare the following solution:
200 mL of 2.5% Glutaraldehyde from 25% stock Glutaraldehyde in 0.2M Sodium Cacodylate Buffer
So far I know:
Molecular weight of Glutaraldehyde: 100g/mol and Sodium Cacodylate:160g/mol
Assuming the density is 1 of Glutaldehyde, then 25%(1000g)=250g
250g/molecular weight(100g/mol)= 2.5mol/L-->2.5M
After this I have no clue which way to go. Any help would be great.
200 mL of 2.5% Glutaraldehyde from 25% stock Glutaraldehyde in 0.2M Sodium Cacodylate Buffer
So far I know:
Molecular weight of Glutaraldehyde: 100g/mol and Sodium Cacodylate:160g/mol
Assuming the density is 1 of Glutaldehyde, then 25%(1000g)=250g
250g/molecular weight(100g/mol)= 2.5mol/L-->2.5M
After this I have no clue which way to go. Any help would be great.