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maninthesuit
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1. Two identical strings on different cellos are tuned to the 440-Hz A note. The peg holding one of the strings slips, so its tension is decreased by 1.5%. What is the beat frequency heard when the strings are played together?
f₁=440Hz; Tension decrease=1.5%2. f(beat)=|f₁-f₂|3.
f₂=440Hz - (440Hz*.015)=433.4Hz
f(beat)=|440Hz-433.4Hz|=6.6Hz
The answer is supposed to be 3.3Hz. I would really appreciate the help. Thanks.
f₁=440Hz; Tension decrease=1.5%2. f(beat)=|f₁-f₂|3.
f₂=440Hz - (440Hz*.015)=433.4Hz
f(beat)=|440Hz-433.4Hz|=6.6Hz
The answer is supposed to be 3.3Hz. I would really appreciate the help. Thanks.