- #1
Kris1
- 29
- 0
Hi,
My question in my Stewart Calculus book is the same as
http://faculty.tru.ca/smcguinness/M317W11/M317W11quiz4sol.pdf
However when I work out the solution I seem to get a different value. My solution is
integral from 0 to 2pi 16 <2cos^2t,2sin^2t,cos(t)sin(t)>
64 integral from 0 to 2pi -cos^2t*sin(t)+sin^2t+cos(t)
I'm not sure however as to whether I am on the right track. Can someone show me what the value of F(r(t)) is and if my solution is on the right track?
Sorry about the formatting.
My question in my Stewart Calculus book is the same as
http://faculty.tru.ca/smcguinness/M317W11/M317W11quiz4sol.pdf
However when I work out the solution I seem to get a different value. My solution is
integral from 0 to 2pi 16 <2cos^2t,2sin^2t,cos(t)sin(t)>
64 integral from 0 to 2pi -cos^2t*sin(t)+sin^2t+cos(t)
I'm not sure however as to whether I am on the right track. Can someone show me what the value of F(r(t)) is and if my solution is on the right track?
Sorry about the formatting.