Help with conditional probability

In summary: Idk if people haven't answered because i didn't show work or not but there isn't much work to show in the first place here's what i tried anyway. In summary, a number is selected randomly from a container containing all the integers from 10 to 50, and the following three probabilities are calculated:a) p(even|greater than 40) = \frac{P(\text{even})}{P(\text{> 40})}b) p(greater than 40| even) = \frac{P(\text{> 40 AND even})}{P(\text{even})}c) p(prime| between 20 and 40) = \frac{P(\
  • #1
imjello
2
0
A number is selected randomly from a container containing all the integers from 10 to 50 find

a) p(even|greater than 40)
b) p(greater than 40| even)
c) p(prime| between 20 and 40)

please provide an explanation, thanks a lot =D
 
Physics news on Phys.org
  • #2
Idk if people haven't answered because i didn't show work or not but there isn't much work to show in the first place here's what i tried anyway.

a. probability its even .5 (5/10)/ probability its greater than 40(1/5) .2 = 2.5 which is over one so obviously wrong

b. probability its greater than 40(1/5) .2 / .5= .4

c. (26/50).52/ (20/50) .4 = 1.3 once again over one

i feel stupid for not understanding how to do these i understand when its in a chart but can't get these question
 
  • #3
I'll give an example: say we wanted to find P(odd | less than or equal to 20). This probability is just the proportion of numbers between 10 and 20 (inclusive) that are odd. These numbers are 11,13,15,17,19; there are 5 of them out of 11 choices, so the the probability sought is 5/11.
 
  • #4
imjello said:
a. probability its even .5 (5/10)/ probability its greater than 40(1/5) .2 = 2.5 which is over one so obviously wrong
Looks like you're thinking that
P(even|greater than 40) = [itex]\frac{P(\text{even})}{P(\text{> 40})}[/itex]
... and that is wrong. It should be
P(even|greater than 40) = [itex]\frac{P(\text{even AND > 40})}{P(\text{> 40})}[/itex]
Try it again.
imjello said:
b. probability its greater than 40(1/5) .2 / .5= .4
Nope. Like in part a, the setup would be
P(greater than 40| even) = [itex]\frac{P(\text{> 40 AND even})}{P(\text{even})}[/itex]
 
  • #5
imjello said:
A number is selected randomly from a container containing all the integers from 10 to 50 find

a) p(even|greater than 40)
There are 10 numbers in the container that are larger than 40. How many of them are even?

b) p(greater than 40| even)
There are 21 numbers in the container that are even. How many of them are greater than 40?

c) p(prime| between 20 and 40)
There are 19 numbers in the container between 20 and 40. How many of them are prime?
(I am assuming that "between 20 and 40" means 21 to 39.

please provide an explanation, thanks a lot =D
 

FAQ: Help with conditional probability

1. What is conditional probability?

Conditional probability is the likelihood of an event occurring given that another event has already occurred. It is expressed as P(A|B), where A is the event of interest and B is the known event.

2. How do you calculate conditional probability?

Conditional probability can be calculated by dividing the probability of the intersection of the two events (P(A∩B)) by the probability of the known event (P(B)). This can also be written as P(A|B) = P(A∩B) / P(B).

3. What is the difference between conditional and unconditional probability?

Conditional probability takes into account the occurrence of a known event, while unconditional probability does not. Unconditional probability is the likelihood of an event occurring without any prior knowledge or condition.

4. Can you give an example of conditional probability?

One example of conditional probability is the likelihood of getting a head on a coin toss given that the coin is fair. The probability of getting a head is 0.5, but if we know that the coin is fair, the probability becomes 1.

5. How is conditional probability used in real life?

Conditional probability is used in many real-life applications, such as in medical diagnosis, weather forecasting, and risk assessment. It allows us to make more accurate predictions and decisions by taking into account the likelihood of an event given certain conditions.

Similar threads

Back
Top