Help with Derivatives of f(g(h(x))) - I'm Stuck!

  • Thread starter hawkblader
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In summary, the conversation is about finding the derivative of the function f(x) = sqrt(sin(e^(x^4*sinx))). The person is having trouble solving it and has tried using composition function and the product rule, but their answer is still incorrect. They ask for help in finding where they went wrong and how to solve it.
  • #1
hawkblader
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Homework Statement



Let f(x) = sqrt(sin(e^(x^4*sinx)))

Find f '(x)

I tried this many times and it's really frustrating!

I made it a composition function : f(g(h(x)))

but I'm not getting the answer at all.

At the end, I found :
1/2(sin(e^((x^4)(sinx))))^(-1/2) (cos(e^(x^4 sinx))) (e^(x^4 sinx)) (4x^3 cosx)

But it's wrong.

Could someone please tell me where I went wrong or how to solve this please.
 
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  • #2
hawkblader said:
1/2(sin(e^((x^4)(sinx))))^(-1/2) (cos(e^(x^4 sinx))) (e^(x^4 sinx)) (4x^3 cosx+4*3x^2 sinx)

You left out the blue part.

ehild
 
  • #3
Could you please tell me how you got the blue part?

I put it in and it's still wrong :(
 
  • #4
hawkblader said:
Could you please tell me how you got the blue part?

I put it in and it's still wrong :(
Product rule.
 
  • #5
hawkblader said:
1/2(sin(e^((x^4)(sinx))))^(-1/2) (cos(e^(x^4 sinx))) (e^(x^4 sinx)) (4x^3 cosx)

Sorry, I also was mistaken, the red part is wrong, as you have to apply the product rule on x4sinx.

ehild
 

FAQ: Help with Derivatives of f(g(h(x))) - I'm Stuck!

What is the chain rule?

The chain rule is a formula used to find the derivative of a composite function, which is a function that is composed of two or more functions. It states that the derivative of a composite function is equal to the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function.

How do I apply the chain rule to find the derivative of f(g(h(x)))?

To apply the chain rule, you need to first identify the outer function, the inner function, and their respective derivatives. Then, you can use the formula: f'(g(h(x))) = f'(g(h(x))) * g'(h(x)) * h'(x). Simply substitute the derivatives of each function into the formula and solve for f'(g(h(x))).

Can you provide an example of using the chain rule to find the derivative of a composite function?

Sure! Let's say we have the function f(x) = sin(2x^2). The outer function is sin(x), the inner function is 2x^2, and their respective derivatives are cos(x) and 4x. Using the chain rule, we can find the derivative as follows: f'(x) = cos(2x^2) * 4x = 4xcos(2x^2).

Are there any special cases when using the chain rule?

Yes, there are a few special cases when using the chain rule. One is when the outer function is a constant, in which case its derivative is 0. Another is when the inner function is a constant, in which case its derivative is also 0. In these cases, the chain rule simplifies to f'(g(h(x))) = f'(g(x)) * g'(x).

What are some tips for using the chain rule effectively?

One tip is to always check your work by applying the chain rule in reverse, starting with the derivative and working backwards to the original function. Another tip is to practice simplifying the function before applying the chain rule, which can make the process easier and less prone to errors.

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