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daNAV1GATOR
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[SOLVED] Help with Energy unit ... Joules... EASY!
The sun burns up 3.6 x 10[tex]^{9}[/tex] kg of matter each second.
Using the formula E = mc[tex]^{2}[/tex], determine how much energy the
sun releases each second. [Speed of light: 3 x 10[tex]^{8}[/tex] m[tex]/[/tex]s]
E = mc[tex]^{2}[/tex]
E = mc[tex]^{2}[/tex]
. .= (3.6 x 10[tex]^{9}[/tex] kg)(3 x 10[tex]^{8}[/tex] m[tex]/[/tex]s)[tex]^{2}[/tex]
. .= (3.6 x 10[tex]^{9}[/tex] kg)(9 x 10[tex]^{16}[/tex] m[tex]^{2}[/tex][tex]/[/tex]s[tex]^{2}[/tex])
. .= 32.4 x 10[tex]^{25}[/tex] [tex]\frac{kg \cdot m^2}{s^2}[/tex]
Now I'm stumped with what to do with the units... I know it should be Joules per second. But how do I show in my solution that Joules will come out? Joules is N[tex]\cdot[/tex]m!
Do I have to change the kg into N? ... My textbook says that the magnitude of c[tex]^{2}[/tex] is 9 x 10[tex]^{16}[/tex] Joules per kilogram.
Please check my calculations also!
Thank You!
Homework Statement
The sun burns up 3.6 x 10[tex]^{9}[/tex] kg of matter each second.
Using the formula E = mc[tex]^{2}[/tex], determine how much energy the
sun releases each second. [Speed of light: 3 x 10[tex]^{8}[/tex] m[tex]/[/tex]s]
Homework Equations
E = mc[tex]^{2}[/tex]
The Attempt at a Solution
E = mc[tex]^{2}[/tex]
. .= (3.6 x 10[tex]^{9}[/tex] kg)(3 x 10[tex]^{8}[/tex] m[tex]/[/tex]s)[tex]^{2}[/tex]
. .= (3.6 x 10[tex]^{9}[/tex] kg)(9 x 10[tex]^{16}[/tex] m[tex]^{2}[/tex][tex]/[/tex]s[tex]^{2}[/tex])
. .= 32.4 x 10[tex]^{25}[/tex] [tex]\frac{kg \cdot m^2}{s^2}[/tex]
Now I'm stumped with what to do with the units... I know it should be Joules per second. But how do I show in my solution that Joules will come out? Joules is N[tex]\cdot[/tex]m!
Do I have to change the kg into N? ... My textbook says that the magnitude of c[tex]^{2}[/tex] is 9 x 10[tex]^{16}[/tex] Joules per kilogram.
Please check my calculations also!
Thank You!