Help with Hagen-Poiseuille Flow

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In summary, the velocity profile for flow through a pipe can be derived without using information from the other coordinate equations.
  • #1
teeeeee
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Hi

I'm trying to derive the velocity profile for Hagen-Poiseuille flow through a pipe.
Using cylindrical coordinates (z direction horizontal), I began by applying the Navier-Stokes equations to each coordinate.

For z, I got: [tex]\frac{1}{\eta}[/tex] [tex]\frac{\partial p}{\partial z} = \frac{1}{\rho}[/tex] [tex]\frac{\partial}{\partial\rho}[/tex] [tex](\rho \frac{\partial v_{z}}{\partial\rho})[/tex] and from this equation I got the result that [tex]v_{z} = \frac{1}{4\eta} \frac{\partial p}{\partial z} (\rho^{2} - R^{2})[/tex] where R is the radius of the pipe

The Navier-Stokes equations for the [tex]\rho[/tex] and [tex]\phi[/tex] directions give [tex]\frac{\partial p}{\partial \rho} = \mu g_{\rho}[/tex] and [tex]\frac{\partial p}{\partial \phi} = \mu g_{\phi}[/tex] respectively, where g is gravity in each direction and [tex]\mu[/tex] is the density of the fluid.

I know that when deriving the velocity profile for flow between parallel plates, you need to use the [tex]\phi[/tex] and [tex]\rho[/tex] equations to show what is a function of what, and what is independent of what.
However, I've managed to get the velocity profile without using any information from the other two coordinate equations. Have I missed something? Do I need to use these two equations for something?

Many thanks
teeeeee
 
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  • #2
Let me walk you from the beginning. If we assume fully-developed flow, then the velocity becomes purely axial, and varies only with the lateral coordinates, that is:
[tex]
\begin{equation}
\begin{split}
v=w=0 \\
u=u(y,z)
\end{split}
\end{equation}
[/tex]
The continuity and momentum equations can then reduce to:
[tex]
\begin{equation}
\begin{split}
\frac{\partial u}{\partial x}=0 \\
-\frac{\partial \hat{p}}{\partial x} + \mu\left(\frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2}\right) = 0 \\
-\frac{\partial \hat{p}}{\partial y} = -\frac{\partial \hat{p}}{\partial y}
\end{split}
\end{equation}
[/tex]
These indicate that the total pressure is a function only of x. Since u does not vary with x, we can say that the gradient dp*/dx must be a negative constant. Then, we can combine to form the basic equation as:
[tex]
\frac{\partial^2 u}{\partial y^2} + \frac{\partial^2 u}{\partial z^2} = \frac{1}{\mu}\frac{d\hat{p}}{dx} = \mbox{const}
[/tex]
We can then non-dimensionalize as:
[tex]
\begin{equation}
\begin{split}
y* &= \frac{y}{h} \\
z* &= \frac{z}{h} \\
u* &= \frac{\mu u}{h^2(-d\hat{p}/dx)}
\end{split}
\end{equation}
[/tex]
Where h is a characteristic duct width. OK, now that we have those variables defined, we can rewrite the general equation as:
[tex]
\nabla^{*2}(u*) = -1
[/tex]

OK, we're just about there. Now, for a Hagen-Poiseuille Fow, we have a circular duct, so the single variable is of course r. Non-dimensionally, we can write r*=r/r_o where r_o is the pipe radius. The Laplacian operator in cylindrical coordiantes reduces to:
[tex]
\nabla^2 = \frac{1}{r}\frac{d}{dr}\left(r\frac{d}{dr}\right)
[/tex]

From here you can plug your operator into the general equation using the non-dimensional terms. If you need more help, come back with a good attempt and we can get you the rest of the way.
 

FAQ: Help with Hagen-Poiseuille Flow

What is Hagen-Poiseuille flow?

Hagen-Poiseuille flow is a mathematical model used to describe the flow of a Newtonian fluid through a long, cylindrical tube under steady-state conditions. It takes into account factors such as fluid viscosity, tube radius, and pressure gradient to determine the velocity and flow rate of the fluid.

Why is Hagen-Poiseuille flow important?

Hagen-Poiseuille flow is important because it is used to understand and analyze fluid flow in a wide range of practical applications, such as in pipelines, blood vessels, and industrial processes. It also provides a fundamental understanding of how viscosity and flow rate are related, which is useful in many engineering and scientific fields.

What is the equation for Hagen-Poiseuille flow?

The equation for Hagen-Poiseuille flow is Q = (πΔP r^4) / (8ηL), where Q is the volume flow rate, ΔP is the pressure gradient, r is the tube radius, η is the fluid viscosity, and L is the tube length. This equation is also known as the Poiseuille's law.

How does viscosity affect Hagen-Poiseuille flow?

Viscosity plays a crucial role in Hagen-Poiseuille flow as it determines the resistance of a fluid to flow. Higher viscosity fluids will have a lower flow rate compared to lower viscosity fluids, given the same pressure gradient and tube dimensions. This is because the higher viscosity fluid experiences more internal friction as it moves through the tube.

What are some assumptions made in the Hagen-Poiseuille flow model?

The Hagen-Poiseuille flow model assumes that the fluid is Newtonian (constant viscosity), incompressible, and laminar (smooth, non-turbulent flow). It also assumes that the tube is long and straight, and the fluid is flowing under steady-state conditions. Additionally, the model does not take into account factors such as fluid turbulence or tube wall roughness, which can affect the flow behavior in real-world situations.

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