- #1
TheSaxon
I get an answer for this problem, but its 0 and i think that's wrong. if someone could please, help that'd be great.
Find the work using the Line Integral Method:
W = Integral of ( Vector F * dr)
Vector Field: F(x,y) = (xy^2)i + (3yx^2)j
C: semi circular region bounded by x-axis and y = squareroot(4-x^2) where y = squareroot(4-x^2) is greater than 0.
So where vector is <P,Q>,
Work = Integral of (P dx + Q dy) over the region R.
So I first parameterized the curve to get P,Q,dx,dy in terms of a common variable:
x = 2cost, y = 2sint for 0 <= t <= pi which implies dx = -2sint and dy = 2cost
but when I carry out the integration, the limits of integration end up making my answer go to 0 because they are between 0 and pi and I always end up with a sin(t) in the result of the integral.
Homework Statement
Find the work using the Line Integral Method:
W = Integral of ( Vector F * dr)
Vector Field: F(x,y) = (xy^2)i + (3yx^2)j
C: semi circular region bounded by x-axis and y = squareroot(4-x^2) where y = squareroot(4-x^2) is greater than 0.
Homework Equations
So where vector is <P,Q>,
Work = Integral of (P dx + Q dy) over the region R.
The Attempt at a Solution
So I first parameterized the curve to get P,Q,dx,dy in terms of a common variable:
x = 2cost, y = 2sint for 0 <= t <= pi which implies dx = -2sint and dy = 2cost
but when I carry out the integration, the limits of integration end up making my answer go to 0 because they are between 0 and pi and I always end up with a sin(t) in the result of the integral.