- #1
sneaky666
- 66
- 0
1.
Suppose P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
a) Must we have P((0,1/2]) <= 1/3 ?
b) Must we have P([0,1/2]) <= 1/3 ?
My answer - Please correct me if i am wrong
a)
P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
lim P([0,1/2])
n-> infinity
so then P((0,1/2]) is a subset of P([1/n,1/2]) for all n = 1,2,3,...
because any number in (0,1/2] can lie in [1/n,1/2] provided the correct n value is in -> 1,2,3...
so true
b)
P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
lim P([0,1/2])
n-> infinity
so then P([0,1/2]) does not equal P([1/n,1/2]) for all n = 1,2,3,...
because as n approaches infinity, the limit of 1/n goes to 0, but doesn't touch 0
so false
2.
Suppose P((0,1/2]) = 1/3. Prove that there is some n such that P([1/n,1/2]) > 1/4.
lim P([1/n,1/2]) = P([0,1/2]) > 1/3 > 1/4
n -> infinity
i don't think this is entirely right, i sort of guessed...
Suppose P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
a) Must we have P((0,1/2]) <= 1/3 ?
b) Must we have P([0,1/2]) <= 1/3 ?
My answer - Please correct me if i am wrong
a)
P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
lim P([0,1/2])
n-> infinity
so then P((0,1/2]) is a subset of P([1/n,1/2]) for all n = 1,2,3,...
because any number in (0,1/2] can lie in [1/n,1/2] provided the correct n value is in -> 1,2,3...
so true
b)
P([1/n,1/2])<= 1/3 for all n = 1,2,3,...
lim P([0,1/2])
n-> infinity
so then P([0,1/2]) does not equal P([1/n,1/2]) for all n = 1,2,3,...
because as n approaches infinity, the limit of 1/n goes to 0, but doesn't touch 0
so false
2.
Suppose P((0,1/2]) = 1/3. Prove that there is some n such that P([1/n,1/2]) > 1/4.
lim P([1/n,1/2]) = P([0,1/2]) > 1/3 > 1/4
n -> infinity
i don't think this is entirely right, i sort of guessed...