- #1
mathzeroh
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help with some trigonometry problems please!
hello everybody! how's everyone doing? i hope you guys are well and your homework is going great!
i posted another help thread but it was in the wrong section! sorry! but i got great help there!
ok here's my new problem. i tried, but i just don't know how i could do it! it's a bit long but please bear with me.
Write each rectangular equation in polar form.
26. y=-5
27. x=10
28. x^2+y^2=7 (latex version: [tex] x^{2}+y^2=7[/tex])
29. 2x^2+2y^2=5y (latex version:[tex]2x^{2}+2y^{2}=5y[/tex])
This is what i did:
26: y=-5 ===> I used the pythagorean theorem: r=√(x^2+y^2)
r=√(x^2+(-5)^2) ---> I plugged in the value for y into this formula
r=√(x^2+25) ---> -5 squared is 25
r=5+√(x^2) ---> 25 square rooted is 5
r=5+x ---> the square root of x squared is x...isn't it?[?]
and also, i said that θ=Undefined because they did not give me an "x" value, so i just said that x=0; because, the formula
for converting a rectangular coordinate to polar coordinate is:
[tex]\theta=tan^{-1}(y/x)[/tex], when x>0
and x cannot be zero in the denominator spot right?
and that's what my answer is. but i have this feeling that it is not right! because i did the next problem which is very similar
to this one. (and sadly the answers are not in the back of the book for even number problems)
27: basically i did the same exact thing as number 26, and got this:
r=10+y --->again, here, θ=zero because of the same reason up there (except this time i didn't have a "y" value, so i said
y=0 and got zero because arctan 0=0).
so i checked in the back to see if this one was right, but it wasn't.[b(] [b(] this is what was there (the answer for #27)
r=10secθ
HELP!
then, i got to number 28, and i didn't have a clue as to how to even begin this problem! same with 29! can someone please
help me with these? any help is appreciated! thanks a lot in advance!
hello everybody! how's everyone doing? i hope you guys are well and your homework is going great!
i posted another help thread but it was in the wrong section! sorry! but i got great help there!
ok here's my new problem. i tried, but i just don't know how i could do it! it's a bit long but please bear with me.
Write each rectangular equation in polar form.
26. y=-5
27. x=10
28. x^2+y^2=7 (latex version: [tex] x^{2}+y^2=7[/tex])
29. 2x^2+2y^2=5y (latex version:[tex]2x^{2}+2y^{2}=5y[/tex])
This is what i did:
26: y=-5 ===> I used the pythagorean theorem: r=√(x^2+y^2)
r=√(x^2+(-5)^2) ---> I plugged in the value for y into this formula
r=√(x^2+25) ---> -5 squared is 25
r=5+√(x^2) ---> 25 square rooted is 5
r=5+x ---> the square root of x squared is x...isn't it?[?]
and also, i said that θ=Undefined because they did not give me an "x" value, so i just said that x=0; because, the formula
for converting a rectangular coordinate to polar coordinate is:
[tex]\theta=tan^{-1}(y/x)[/tex], when x>0
and x cannot be zero in the denominator spot right?
and that's what my answer is. but i have this feeling that it is not right! because i did the next problem which is very similar
to this one. (and sadly the answers are not in the back of the book for even number problems)
27: basically i did the same exact thing as number 26, and got this:
r=10+y --->again, here, θ=zero because of the same reason up there (except this time i didn't have a "y" value, so i said
y=0 and got zero because arctan 0=0).
so i checked in the back to see if this one was right, but it wasn't.[b(] [b(] this is what was there (the answer for #27)
r=10secθ
HELP!
then, i got to number 28, and i didn't have a clue as to how to even begin this problem! same with 29! can someone please
help me with these? any help is appreciated! thanks a lot in advance!
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