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shenzys
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Homework Statement
Q) Calculate the volume of 0.1M HCl you would need to add to 200ml of 0.15M sodium acetate solution to obtain a buffer of pH 4.2.
Ka = 1.74 * 10^-5 moldm-3
Homework Equations
pH = pKa + log [salt]/[acid]
The Attempt at a Solution
Log[salt]/[acid] = pH - pKa
[salt]/[acid] = 0.275
Equation: [salt] = 0.275 [acid]
[salt] = 200*0.15/200+v
[acid] = (0.1*V / 200+v) - (200*0.15/200+v)
Substituting into above equation:
200*0.15/200+v = 0.275(0.1*V/200+v) - 0.275(200*0.15/200+v)
30 = 0.0275v - 8.25
38.25= 0.0275v
V = 38.25/0.0275v
V = 1390 cm^3
This is obviously wrong! Where did I go wrong?