High-energy physics: momentum transfer

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The discussion focuses on calculating the square of the four-momentum transfer, q², in a collision between a 20 GeV electron and a stationary proton. The user initially derives q² using the four-momentum vectors but is confused about the negligible mass assumption for the electron and how it affects the calculations. Key points include the need to apply conservation of energy and momentum to determine the final momentum and energy of the electron after the collision. The analogy to Compton scattering is suggested, emphasizing that the small deflection implies the electron retains most of its energy. The user is advised against ignoring terms and to solve for the unknown energy E' to proceed with the calculation.
Chiborino
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Homework Statement


I have an electron of 20 GeV and negligible mass that collides with a stationary proton (mc^2 = 9.38 GeV) and deflects at an angle of 5°. I'm asked to find the square of the four-momentum transfer, q2

Homework Equations


q = P - P', where P/P' is a 4-momentum vector <px, py, pz, iE>
a "primed" quantity represents a value after the collision with the proton.

The Attempt at a Solution


I took the quantity P-P' and squared it:
q2 = (P-P')*(P-P') = P2 + P'2 -2P*P'
I'm told the first two terms are negligible due to the electron's mass being negligible, but I'm not sure I see the sense in that.
Anyways, continuing on, I then have:
q2 = -2P*P' = -2(px*px' + py*py'+pz*pz' -E*E')
or q2 = -2p*p' + 2E*E'
This is where I'm stuck. Should I also assume the product of the 3-momenta is 0 and carry on with the +2EE' term I'm left with? And what do I even do about the E' since I don't know that quantity?
 
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Chiborino said:

Homework Statement


I have an electron of 20 GeV and negligible mass that collides with a stationary proton (mc^2 = 9.38 GeV) and deflects at an angle of 5°. I'm asked to find the square of the four-momentum transfer, q2
That's a pretty massive proton!


Homework Equations


q = P - P', where P/P' is a 4-momentum vector <px, py, pz, iE>
a "primed" quantity represents a value after the collision with the proton.

The Attempt at a Solution


I took the quantity P-P' and squared it:
q2 = (P-P')*(P-P') = P2 + P'2 -2P*P'
I'm told the first two terms are negligible due to the electron's mass being negligible, but I'm not sure I see the sense in that.
Anyways, continuing on, I then have:
q2 = -2P*P' = -2(px*px' + py*py'+pz*pz' -E*E')
or q2 = -2p*p' + 2E*E'
This is where I'm stuck. Should I also assume the product of the 3-momenta is 0 and carry on with the +2EE' term I'm left with? And what do I even do about the E' since I don't know that quantity?
With the small deflection, you would expect that the electron didn't give up much of its energy, so you wouldn't expect the product of the three-momenta to vanish. Unfortunately, you're not going to be able to just erase terms you don't want to deal with.

You need to use conservation of energy and momentum to figure out ##\vec{p}'## and E'. Note that because the electron is essentially massless in this problem, the situation is essentially the same as Compton scattering.
 

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