Homework help: Dropping a sand bag from a Hot Air Balloon

In summary, the scenario involves analyzing the effects of dropping a sandbag from a hot air balloon. When the bag is released, it will initially remain at the same altitude as the balloon before beginning to fall due to gravity. The speed of the bag will increase as it descends, while the balloon continues to rise or stay stable. Key factors to consider include the height of the balloon, the velocity of the bag upon release, and the effects of air resistance on the falling object. This situation can illustrate concepts of gravity, motion, and the principles of physics involved in free-fall dynamics.
  • #1
Clockclocle
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Homework Statement
Suppose an air baloon keep raising with constant velocity v0, at time t=0 the sand bag attached to it drop at rest.
Relevant Equations
y=vo-1/2gt^2
In this situation should my free fall equation contain the v0 of the baloon or I should deny it. Because it seems to me that there is no outer force acts on the sandbag, so the scenario is just the same as I climb to the same height at time t=0 and drop the sandbag at rest.
 
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  • #2
Clockclocle said:
so the scenario is just the same as I climb to the same height at time t=0 and drop the sandbag at rest.
What if the balloon is rising at the speed of a rifle bullet? You are riding on the balloon holding the sandbag in your hand and let it go.
 
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  • #3
I see the mistake, I thought that it gonna fall below me so it would be the same when I stand still. But in this case I keep moving with velocity v0.
 
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  • #4
Clockclocle said:
##\dots## so the scenario is just the same as I climb to the same height at time t=0 and drop the sandbag at rest.
The acceleration is the same not the scenario. In the first case the velocity of the bag relative to the ground is the same as that of the balloon whilst in the second case it is zero. Different initial velocities mean different free fall trajectories.
 
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FAQ: Homework help: Dropping a sand bag from a Hot Air Balloon

What factors influence the time it takes for the sandbag to hit the ground?

The time it takes for the sandbag to hit the ground is influenced by the initial height from which it is dropped, the initial velocity of the hot air balloon (if it is moving), and the acceleration due to gravity. Air resistance can also play a role, but it is often negligible in basic physics problems.

How do you calculate the time it takes for the sandbag to reach the ground?

To calculate the time it takes for the sandbag to reach the ground, you can use the kinematic equation: \( t = \sqrt{\frac{2h}{g}} \), where \( t \) is the time in seconds, \( h \) is the height in meters, and \( g \) is the acceleration due to gravity (approximately 9.81 m/s²). This equation assumes that the sandbag is dropped from rest and air resistance is negligible.

What is the impact velocity of the sandbag when it hits the ground?

The impact velocity of the sandbag can be calculated using the kinematic equation: \( v = \sqrt{2gh} \), where \( v \) is the final velocity in meters per second, \( g \) is the acceleration due to gravity, and \( h \) is the height from which the sandbag is dropped. This equation also assumes negligible air resistance.

How does the initial velocity of the hot air balloon affect the sandbag's motion?

If the hot air balloon is moving upward or downward when the sandbag is dropped, the initial velocity of the sandbag will be the same as the velocity of the balloon at the moment of release. This initial velocity must be taken into account when calculating the sandbag's trajectory and time to hit the ground using kinematic equations.

How can air resistance be accounted for in the calculations?

To account for air resistance, you would need to use more complex equations that include drag force. The drag force depends on the shape and size of the sandbag, the density of the air, and the velocity of the sandbag. These factors make the equations more complicated and typically require numerical methods or simulations for precise calculations.

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