- #36
quantster
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matt grime said:So if i declare f(x)=x^2+y^2, and then declare g(x) to be the square root of f(x), in what way it that not sqrt(x^2+y^2)?
Very intereting posts and emotions. To be consistent with the original notations of matt, he could have written g(x) to be square root of f(x,y) and not f(x), as he defined f(x,y) and not f(x) to be x^2+y^2.