Horizontal circular motion problem

In summary, the student attempted to find the length of the string using 2pi*r and then used the sine inverse to find the angle. However, they realized they made a mistake and are seeking help.
  • #1
psstudent
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0

Homework Statement


I have this question to solve for homework : " An object of mass 10 kg is whirled around a horizontal circle of radius 4m" If the uniform speed of the object is 5m/s Calculate a) tension in string b) angle of inclination of string to the vertical.

Homework Equations

The Attempt at a Solution


Here is what I tried: I thought of finding the length of the entire string so using 2pi*r I got 25.12. then using the sine inverse of that to get the angle i got 4(radius)/25.12 =.16 sine inverse which would give an angle of 9.2 degrees. then I used tension = mg/cos(theta) = 10 * 9.81/.99 = 99.1 N.

I also tried to work out the angle a different way using k=.5mv2 to find energy which gave me 125 Joules and then i plugged that into the potential energy formula to give me the height so potential energy = mgh thus

h= energy/g*m which gave me 1.27m. then i used CAH trignometry to give me .9 cos inverse = 26degrees. This was the method I used to solve a momentum question but I doubt it works in this case.

Now I realize I made a mistake which is why I am coming here. I thought I had found the length of the string when i used 2pi*r but iI realized I actually just found the perimeter of the circle the radius made. Any help would be appreciated.
 
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  • #2
You are given the radius of the horizontal circle of the motion as well as the speed of the mass. You should be able to calculate the centripetal force that is required to keep the given mass moving along that circular path. You should also be able to find the gravitational force acting on that mass. The tension in the rope must provide the force to balance both of those forces. So their Draw a Free Body Diagram for the mass at a given instant, sketching the various force vectors. See if you can't find a relationship between those forces.
 
  • #3
Thanks for the reply, but i figured it out. I got the vertical and horizontal components use Pythagorean theorem and then SOH to find the answer
 
  • #4
pls help sketch the diagram of the question above cos I really don't understand it@gneill thanks
 
  • #5
Esty101 said:
pls help sketch the diagram of the question above cos I really don't understand it@gneill thanks
Why don't you give it a try first? Post your sketch attempt.
 

FAQ: Horizontal circular motion problem

What is horizontal circular motion?

Horizontal circular motion is a type of motion in which an object moves in a circular path on a horizontal plane, maintaining a constant distance from the center of the circle.

What is the difference between horizontal circular motion and vertical circular motion?

The main difference between horizontal and vertical circular motion is the orientation of the circle. In horizontal circular motion, the circle lies on a horizontal plane, while in vertical circular motion, the circle lies on a vertical plane.

How is centripetal force related to horizontal circular motion?

Centripetal force is the force that keeps an object moving in a circular path. In horizontal circular motion, the centripetal force acts towards the center of the circle, causing the object to maintain its circular path.

What is the formula for calculating the speed of an object in horizontal circular motion?

The formula for calculating the speed of an object in horizontal circular motion is v = √(r * ω), where v is the speed, r is the radius of the circle, and ω is the angular velocity.

How does the mass of an object affect its horizontal circular motion?

The mass of an object does not affect its horizontal circular motion. As long as the object is moving at a constant speed and the centripetal force is acting on it, the mass will not change the motion of the object.

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