- #1
jehan4141
- 91
- 0
This problem has 2 stars in my book, which means it is supposed to pretty difficult. I got the answer fairly easily and am worried that maybe I missed something important and thus got the incorrect answer too easily. No answer is provided to self-check my answer to see whether or not I am approaching the problem correctly, so would you mind telling me if my work is correct? I know this site isn't a place to have your work checked, but I just want to make sure I am doing this correctly because the problem seemed easier than 2 stars. I usually can't finish a 2 star problem. Thank you!
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A kite is hovering over the ground at the end of a 43-m line. The tension in the line has a magnitude of 16 N. Wind blowing on the kite exerts a force of 19 N, directed 56 degrees above the horizontal. Note that the line attached to the kites is NOT oriented at an angle of 56 degrees above the horizontal. find the height of the kite, relative to the person holding the line.
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MY APPROACH:
Givens:
Length, L = 43 m
Tension, T = 16 N
Force of wind, Fw = 19 N, 56 degrees above the horizontal
From the problem, I understand that the kite is hovering in one spot. Thus, all horizontal and vertical forces equal to zero.
By setting the horizontal forces to zero, I get:
ΣFx = (Fw)cos56 - TcosΘ = 0
Fwcos56 = TcosΘ
19cos56 = 16cosΘ
Θ = 48.39116057
Using the value of Θ we have just found, I can use
sinΘ = height / hypotenuse to find the height of the kite.
sin(48.39116057) = height / 43
height = 32.15091308
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A kite is hovering over the ground at the end of a 43-m line. The tension in the line has a magnitude of 16 N. Wind blowing on the kite exerts a force of 19 N, directed 56 degrees above the horizontal. Note that the line attached to the kites is NOT oriented at an angle of 56 degrees above the horizontal. find the height of the kite, relative to the person holding the line.
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MY APPROACH:
Givens:
Length, L = 43 m
Tension, T = 16 N
Force of wind, Fw = 19 N, 56 degrees above the horizontal
From the problem, I understand that the kite is hovering in one spot. Thus, all horizontal and vertical forces equal to zero.
By setting the horizontal forces to zero, I get:
ΣFx = (Fw)cos56 - TcosΘ = 0
Fwcos56 = TcosΘ
19cos56 = 16cosΘ
Θ = 48.39116057
Using the value of Θ we have just found, I can use
sinΘ = height / hypotenuse to find the height of the kite.
sin(48.39116057) = height / 43
height = 32.15091308