- #1
xrayzulu
- 2
- 0
Hello all.
I am give a pin jointed truss structure. (Look at attached jpeg image)
I have a worked solution of:
F2*4 + F1*3-Av*6=0
Av=1/6(3F1+4F2)=600kN
Ch=F2=600kN
Cv=Av-F1=200kN
Member forces:
S1=-5/4 Av = -750kN
S2=-CH=-600kN
S5=3/4 Av=450kN
S3=-5/4 s4=250kN
S4=-Cv=-200kN
l1=5m l2=3m l3=5m l4=4m l5=6m
-----------------------------------
What I don't understand is how the member forces are worked out in the solution I am given, if some one could explain this.
Thanks!
I am give a pin jointed truss structure. (Look at attached jpeg image)
I have a worked solution of:
F2*4 + F1*3-Av*6=0
Av=1/6(3F1+4F2)=600kN
Ch=F2=600kN
Cv=Av-F1=200kN
Member forces:
S1=-5/4 Av = -750kN
S2=-CH=-600kN
S5=3/4 Av=450kN
S3=-5/4 s4=250kN
S4=-Cv=-200kN
l1=5m l2=3m l3=5m l4=4m l5=6m
-----------------------------------
What I don't understand is how the member forces are worked out in the solution I am given, if some one could explain this.
Thanks!